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Maru [420]
3 years ago
11

Which shows one way to determine the factors of 4x3 x2 – 8x – 2 by grouping? x2(4x 1) – 2(4x 1) x2(4x – 1) 2(4x – 1) 4x2(x 2) –

1(x 2) 4x2(x – 2) – 1(x – 2)
Mathematics
1 answer:
liberstina [14]3 years ago
4 0

An expression has numbers, variables, and mathematical operations. The factors of the expression 4x³+x²-8x-2 by grouping are x²(4x+1)-2(4x+1).

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The factors of the expression by grouping can be done as,

4x^3+x^2-8x-2

Take x² as the common factor from the first two terms while -2 from the last two terms,

4x^3+x^2-8x-2\\\\=x^2(4x+1)-2(4x+1)

Thus, the factors of the expression 4x³+x²-8x-2 by grouping are x²(4x+1)-2(4x+1).

Learn more about Expression:

brainly.com/question/13947055

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How do I solve for x
Alchen [17]
Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
a^2+b^2=c^2

Input the information from the diagram into the formula: 
(x)^2+(x+7)^2=(13)^2

Expand each term:
(x)^2+(x+7)^2=(13)^2

x^2+((x+7)(x+7))=169

x^2+(x(x+7)+7(x+7))=169

x^2+x^2+7x+7x+49=169

Combine like terms:
2x^2+14x+49=169

Add -169 to both sides:
(2x^2+14x+49)+(-169)=(169)+(-169)

2x^2+14x-120=0

Factor out the Common Term (2):
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Factor the Complex Trinomial:
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2(x(x-5)+12(x-5))=0

2(x-5)(x+12)=0

Set Factors to equal 0:
x-5=0

x=5

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x+12=0

x=-12

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is: 
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I hope this helped!
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3 years ago
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Answer: 7

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