Answer:
3x^2 + 3xy + 6y
Step-by-step explanation:
The answer is 11 if i recall correctly.
Answer:
That is 6 divided by 3/8, better written as
6
--
1
====
3
--
8
Invert the 3/8 and then multiply:
6 8
-- * ---
1 3
Reduce 6/3: 6/3 = 2
Then you have 2(8), or 16 (answer)
Y = mx + b
First equation 1 = m(4) + b, bring everything to one side m(4) + b - 1 = 0
Second equation 7 = m(5) + b, bring everything to one side m(5) + b - 7 = 0
Set them equal to each other,
m(4) + b - 1 = m(5) + b - 7
If you bring the b over to the left hand side it becomes
m(4) + b - b - 1 = m(5) - 7
m(4) - 1 = m(5) - 7
Solve for m
6 = m
Plug m = 6 into either equation from the beginning,
m(4) + b - 1 = 0
6(4) + b - 1 = 0
24 + b - 1 = 0
b = -23
Knowing m and b we can now make an equation
y = mx + b
y = 6x -23 Final answer
According to your image which has a diagram where 2 planes are both perpendicularly attached to each other. So base on your diagram I conclude that the answer is C. There are two segments along the planes intersect. I hope i answered your question
