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3 years ago

Solving Absolute Value Equations: Solve 4|x+7|+8=32

Mathematics

1 answer:

Len [333]3 years ago

3 0

Here’s if you need it written out

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Pls help picture provided :}

Liono4ka [1.6K]

Answer:

not sure but positive 3?

4 0

3 years ago

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A mother is to give her child 10 ccs of medicine every

8090 [49]

Answer:

See below in bold.

Step-by-step explanation:

1 teaspoon holds 5 ccs so that is 2 teaspoons per dose.

2 teaspoons every 6 hours is 4 * 2 = 8 teaspoons per day.

7 0

3 years ago

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Hope made 3 different yo-yo's. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string

Nat2105 [25]

Answer:

See explanation

Step-by-step explanation:

Your question is different from the attachment

Statement 1

1 adult + 5 Children

$4 for adult and total of $16 for both adult and children

Let

Cost of children skating = x

The equation is

4 + 5x = 16

Statement 2:

Cost of making a bike bag= $4

Selling price of the bike bag = $5

Profit = $16

Let x = number of bike bag

Profit = selling price - cost price

16 = 5x - 4x

16 = x(5 - 4)

Also written as

(5 - 4)x = 16

Statement 3:

Initial temperature = 16°C

Change in temperature per hour = 4°C

Final temperature = 5°C

Let

x = number of hours it changes

16 - 4x = 5

Hope made 3 different yo-yos. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string for the second yo-yo, and a total of meters of string 4 1/3

length of first yo-yo = 1 3/4

length of second yo-yo = 1

Length of third yo-yo = x

Total = 4 1/3

Total length = length of first yo-yo + length of second yo-yo + length of third yo-yo

4 1/3 = 1 3/4 + 1 + x

4 1/3 = 2 3/4 + x

4 1/3 - 2 3/4 = x

13/3 - 11/4 = x

(52-33) / 12 = x

19/12 = x

x = 1 7/12

5 0

3 years ago

The five values for a data set are:

dem82 [27]

Answer:

The box-and-whisker plot for the given question is as shown at the attached figure.

Minimum = 11

Lower quartile = Q1 = 12

Median = Q2 = 23.5

Upper quartile = Q3 = 27

Maximum = 33

So, according to the given data and the figure:

The box will go from 12 to 27 ⇒ Q1 to Q3
A line dividing the box will go at 23.5 ⇒ Q2
The left whisker will go from 11 to 12 ⇒ Minimum to Q1
The right whisker will go from to 27 to 33 ⇒ Q2 to Maximum

5 0

3 years ago

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A painting is 2 in tall and 3 in wide. If it is enlarged to a width of 15 in then how tall will it be?

vekshin1

Answer:

10 in

Step-by-step explanation:

Old proportions:

2 x 3

New proportions

h x 15

Assuming the painting has been increased by a constant scale factor.

Where x is the unknown scale factor, and h is the height after it has been enlarged.

$3 * x = 15\\2 * x = h$

Rearrange second equation:

$3 * x = 15\\x =\frac{h}{2}$

Substitute:

$3*\frac{h}{2} =15\\\frac{h}{2}=5\\h=10$

7 0

3 years ago

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