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antiseptic1488 [7]

2 years ago

8

Solving Absolute Value Equations: Solve 4|x+7|+8=32

1 answer:

Len [333]2 years ago

3 0

Here’s if you need it written out

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Hey pls show some working i need some serious help

Elden [556K]

Answer:

$\frac{x^{12}y^{4}}{z^3}$

Step-by-step explanation:

Step 1: Multiply exponents

$\frac{y^{6/6}z^{-6/2}}{x^{-12}y^{-6/2}}$

Step 2: Simplify

$\frac{yz^{-3}}{x^{-12}y^{-3}}$

Step 3: Flip the negative exponents

$\frac{x^{12}y^{4}}{z^3}$

8 0

3 years ago

If y=1/2x+4, then find the equation of the line parallel through the point (6,3).

tatyana61 [14]

Answer:

x=2y

Step-by-step explanation:

random guess

5 0

2 years ago

We are studying the proportion of cities that have private garbage collector. We want a maximum error of 0.10 and a 95% confiden

True [87]

Answer:

The minimum number of cities we need to contact is 96.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

In this problem, we have that:

$p = 0.5, M = 0.1$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.1 = 1.96*\sqrt{\frac{0.5*0.5}{n}}$

$0.1\sqrt{n} = 0.98$

$\sqrt{n} = 9.8$

$(\sqrt{n})^{2} = (9.8)^{2}$

$n = 96$

The minimum number of cities we need to contact is 96.

8 0

2 years ago

The average price (in dollars) to rent a studio in a certain city can be approximated by the equation p=28.2t+644 where t is the

egoroff_w [7]

$p = 28.2t + 644\\\\p-644 = 28.2t\\\\\frac{p-644}{28.2} = \frac{28.2t}{28.2}\\ \\t = \frac{p-644}{28.2}$

$t = \frac{1320.80-644}{28.2} \\\\t = 24$

It will take 24 years.

6 0

2 years ago

BEST ANSWER GETS BRAINLIEST!! PLEASE HELP

Natasha_Volkova [10]

4 units wide........................

7 0

3 years ago

Read 2 more answers