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2 years ago

The local newspaper has letters to the editor from 40 people. If this number represents 4% of all of

Mathematics

1 answer:

Setler79 [48]2 years ago

4 0

Answer:

1000 readers

Step-by-step explanation:

40 people represent 4% of the total number of readers.

4% is 1/25 of 100%, therefore:

4% x 25 = 100%

So, if we multiply the number of people that represent 4% by 25, we will get the total number (100%).

40 x 25 = 1,000

The newspaper has 1000 total readers.

Alternatively, you could also divide 4% (40) by 4 which would give you 1%=10. Multiply this by 100 to get 100% which gives us: 100% = 1000.

Hope this helped!

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A health food store makes trail mix using dried fruit and nuts. The cost of the dried fruit is $2.50 per

Vinil7 [7]

Answer:

cost of dried fruit per pound=2.5 $/pound

cost of nuts per pound =2 $/pound

total cost=225$ =cost of dried fruit +total cost of nuts

To find the cost of dried fruit we need to multiply cost of dried fruit per pound and the number of bounds hence 2.5 x where x is the number of bounds

which is the total cost of dried fruit and consequently 2y is total cost of nuts where y is the weight of nuts in pound

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the area of the shaded region

kogti [31]

Answer:

7. 183 in^2

8. 192.42 m^2

9. 239.4 ft^2

Step-by-step explanation:

7. The figure seems most easily seen as a trapezoid with a triangle removed. The trapezoid has bases of 26 and 14, and a height of 15. So, its area is ...

A = (1/2)(b1 +b2)(h) = (1/2)(26+14)(15) = 300 . . . . . . square inches

The triangle has a base of 26 and a height of 9, so an area of ...

A = (1/2)bh = (1/2)(26)(9) = 117 . . . . . . square inches

Then the shaded area is ...

300 in^2 -117 in^2 = 183 in^2

8. The area of the donut can be found different ways. One way is to multiply the width of the shaded area (3.5 m) by the circumference of its centerline.

The centerline diameter is 21 m - 3.5 m = 17.5 m, so the circumference of that circle is ...

C = πd = π(17.5 m) = 17.5π m

Then the area of the shaded part is ...

(3.5 m)(17.5π m) = 61.25π m^2 ≈ 192.42 m^2

9. As in problem 7, this can be treated as a parallelogram less a triangle. Here, we need to do a little work to find the area of the triangle.

The triangle of interest is a right triangle with hypotenuse 23.8 ft and one leg 21 ft. The Pythagorean theorem can be used to find the other leg:

h = √(23.8^2 -21^2) = √125.44 = 11.2

Then the area of the triangle is ...

A = (1/2)bh = (1/2)(21)(11.2) = 117.6 . . . ft^2

The area of the parallelogram (including the triangle) is ...

A = bh = (23.8 ft)(15 ft) = 357 ft^2

So, the shaded area is the difference ...

357 ft^2 -117.6 ft^2 = 239.4 ft^2

_____

<em>Comment on significant digits</em>

The area in problem 8 may be considered to be 192.325 m^2 if you are required to use 3.14 as the value for pi. Since that value is only good to 3 significant digits, it is quite pointless to report the answer to 6 significant digits when using that value. It is quite reasonable to use 192 m^2 for the answer, especially if you're required to round to whole numbers.