Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.
Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.
x + x + 2 = -36
2x + 2 = -36
2x = -38
x = -19
The smaller one of the two integers is -19.
x + 2 = -19 + 2 = -17
The greater of the two integers is -17.
Answer: The integers are -19 and -17.
Set up the equation. On a piece of paper, write the dividend (number being divided) on the right, under the division symbol, and the divisor (number doing the division) to the left on the outside. ...
Divide the first digit.
Divide the first two digits.
Enter the first digit of the quotient.
(See image attached for an example)
Answer:
y = 8x-37
Step-by-step explanation:
y=mx+c
We know the slope m
y=8x+c
We know a point on the line (5,3). Substitute this in for x and y
3 = 8(5) +c
3 = 40+c
3-40 = 40+c-40
-37 =c
y = 8x-37
1. Plug in -3 for a
14-(-3)^2
14-9
5
Final answer: 5
2. 15 more than r=15+r (notice the keyword more) equals 61
Final answer: r+15=61
i believe it would be -19/48
