2 answers:
Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.
Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.
x + x + 2 = -36
2x + 2 = -36
2x = -38
x = -19
The smaller one of the two integers is -19.
x + 2 = -19 + 2 = -17
The greater of the two integers is -17.
Answer: The integers are -19 and -17.
Let x = one of the integers. To get to the next odd number, you would have to add 2 to the first number so it is x + 2.
"sum" tells us to add.
x + x + 2 = - 36
2x + 2 = - 36
Subtract 2 from both sides to the variable is on one side and constants are on the other.
2x = - 36 - 2
2x = - 38
Divide both sides by 2 to isolate the variable.
x = - 38/2 = - 19
x = - 19
x + 2 = - 19 + 2 = - 17
Your two numbers are -17 and -19.
To check your answer, add them together.
- 17 + (-19) = - 36
-17 - 19 = 36
-36 = -36
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