Answer:
umm...4 last time I checked!
1. the answer is C
2. the answer is D
I would plug in each of the solutions to every equation and see which one works. This is probably easier than solving for x, y, and z. But let me know if you would like me to run through the steps!
First choice: using the first equation, -3(-3)-4(4)+6=-19 not -1 as listed. False.
Second choice: using the first equation, -3(4)-4(-3)+(-1)=-1 ; using the second equation, 2(4)+(-3)-(-1)=6 not -8 as listed. False.
Third choice: using the first equation, -3(-3)-4(4)+8=-17 not -1 as listed. False.
Fourth choice: using the first equation, -3(3)-4(-4)+-(-6)=-1 ; using the second equation,
2(3)+(-4)-(-6)=8 ; using the third equation, 3+8(-4)-(-6)=23
So the answer should be the fourth choice. Hope this helps! :)
Answer:
We can not solve for a unique cost for each soldier.
Step-by-step explanation:
Let x be the daily cost for legionaries and y be the daily cost for archers.
Upon using our given information we will get a system of linear equations as:


Now we will solve for x from our 2nd equation,

Now we will substitute this value in our 1st equation.

We can see that -3y cancels out with 3y and 9 is not equal to 10. So this is an unsolvable system. Therefore, we can not find a unique cost for each soldier.
Answer:
7a. 7b=49ab
Step-by-step explanation: