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3 years ago

The following triangles are similar. Find side AB.

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Set up ratios of corresponding sides. x+2 is to 6 as 2 is to 3:

$\frac{x+2}{6}=\frac{2}{3}$

Now cross multiply to get

3(x + 2) = 12 and

3x + 6 = 12 so

3x = 6 and

x = 2. That means that side AB, x + 2, is 2 + 2 which is 4

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Mkey [24]

Answer:

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Step-by-step explanation:

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3 years ago

Answers A. 5 B. 9 C. 11 D. 13

MA_775_DIABLO [31]

4k-7=2k+3
-2k. -2k

2k-7=3
+7. +7
2k=10
2÷2 2÷10
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Answer D

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4 years ago

Which of thw following is equivalent to √20?

kupik [55]

Answer:

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Step-by-step explanation:

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4 years ago

6k²+16k=0 x²-5x= 0 ANSWer these noeww!

pentagon [3]

Answer:

1) k = (-8)/5

2) x = 5

Step-by-step explanation:

$6 {k}^{2} + 16k = 0$

$= > 2k(3k + 8) = 0$

$= > 3k + 8 = \frac{0}{2k} = 0$

$= > 3k = - 8$

$= > k = \frac{ - 8}{3}$

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$= > x(x - 5) = 0$

$= > x - 5 = \frac{0}{x} = 0$

$= > x = 5$

8 0

3 years ago

Find the value of k if it is known that the line y=kx+2 goes through point:

MrRissso [65]

Answer:

k = -10/7 and k = -3

Step-by-step explanation:

Given: y = kx + 2

where k is the slope of line and 2 is y-intercept.

∵ line y = kx + 2 is passing through point P (-7, 12), ∴ x = -7 and y = 12

Now substituting the value of x and y in above equation,

y = kx + 2

12 = k(-7) + 2

-7k = 12 - 2

- 7k = 10

$k = \frac{-10}{7}$

In the same way, ∵ line y = kx + 2 is passing through point P (3, -7), ∴ x = 3 and y = -7

y = kx + 2

Now substituting the value of x and y in above equation,

-7 = k(3) + 2

3k = -7 - 2

3k = - 9

k = -3

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4 years ago