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Diano4ka-milaya [45]
3 years ago
13

Please tell me the answer to this

Mathematics
1 answer:
Darya [45]3 years ago
5 0

Answer:

43

Step-by-step explanation:

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Which linear equations are parallel to y=3x+5
UkoKoshka [18]

Answer: 3

Step-by-step explanation: i dont really know how to explain the solving

5 0
3 years ago
A housing society consisting of 5500 people needs 100L of water per person per day. the cylindrical supply tank is 7m high and h
Zigmanuir [339]

Water in the tank will last for 1 day.

<u>Step-by-step explanation:</u>

Step 1:

Given diameter of tank = 10m, so radius = 5m,

height of tank = 7m

Number of people in society = 5500, number of L per day per person = 100L

Step 2:

Calculate total liters of water required

⇒ Total L required in the society = 5500 × 100 = 550,000 L

Step 3:

Calculate volume of water in tank in 1 day

⇒ Volume of cylinder = πr²h = 22/7 × 5 × 5 × 7

⇒ Volume = 22 × 25 = 550 m³

⇒ Volume = 550,000 L (since 1 m³ = 1000 L)

Step 4:

Calculate number of days water will last

⇒Number of days = Total water required/Volume of tank

= 550,000/550,000

⇒ Number of days = 1

6 0
4 years ago
A bookstore had 60 copies of a magazine. Yesterday, it sold 1/3 of them. Today, it sold 3/5 of what remained. How many copies do
yKpoI14uk [10]

Answer: 8 copies

Step-by-step explanation:

1/3 of 60 is 20. 1/5 of 40 is 8. 8x3=24, 40-24=16

3 0
3 years ago
Read 2 more answers
As part of her training routine for basketball, Shaylle alternates between cycling and running for exercise. She cycles at a rat
Bezzdna [24]

Answer:

The time taken while cycling is 1 hour

The time taken on running is 3.5 hours

Step-by-step explanation:

Given as :

The speed at which Shaylle cycles = 10 miles per hour

The speed at which Shaylle runs = 6 miles per hour

The Total Time she spend on both exercise  = 4.5 hours

Let The time taken on cycle = t_1 hours = t hour

And The time taken on exercise = t_2 = (4.5 -t) hours

The Total Distance she cover = 41 miles

Let The distance cover by her on cycles = d_1

And The distance cover by her on exercise = d_2

Now, According to question

Distance = Speed × Time

So, For Cycling

d_1 = 10 mph × t_1

Or, d_1 = 10 mph × t hours

Or ,  d_1 = 10 t  miles

For exercise

d_2 = 6 mph × t_2

Or, d_2 = 6 mph × (4.5 - t)  hours

Or ,  d_2 = (27 - 6 t)  miles

Now, Distance = d_1 + d_2

Or ,  D =  d_1 + d_2

or,  10 t   miles +  ( 27 - 6 t) miles = 41 miles

Or,  10 t - 6 t =  41 - 27

Or, 4 t = 14

∴  t = \frac{14}{4}

I.e t = 3.5 hours

So, The time taken on cycle = t_1 hours = t hour

I.e  t_1 = 3.5 hours

And The time taken on exercise = t_2 = (4.5 - t) hours

I.e  t_2 = 4.5 - 3.5 = 1 hour

Hence The time taken while cycling is 1 hour

And The time taken on running is 3.5 hours  Answer

3 0
3 years ago
Find the product: (-3)(-5) All I managed to gather is to multiple -3 * -5 =15 am I missing a step?
Mama L [17]
Not missing a thing... 3 x 5 = 15 and negative x negative is positive! Keep up the good work!
7 0
3 years ago
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