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maw [93]
3 years ago
11

A counter top is 18 feet long and 3 feet wide. What is the area of the counter top in square meters? Use the conversion 1 foot =

0.305 meter. Round your final answer to 2 decimal places.
Mathematics
1 answer:
podryga [215]3 years ago
3 0

Answer:

Area of the counter top is 5.02\ m^2.

Step-by-step explanation:

Given:

Length of the Counter top = 18 feet

Width of the counter top = 3 feet

We need to find the area of the counter top is square meter;

Solution:

Now we need to find the area of the counter top is square meter.

But given data is in feet so we will first convert feet into meters.

1 foot = 0.305 meter.

So 18 feet = Number of meters in 18 feet.

By Using Unitary method we get;

Number of meters in 18 feet = 18\times 0.305 = 5.49\ m

Length of the Counter top = 5.49 m

Also 3 feet = Number of meters in 3 feet.

Again Using Unitary method we get;

Number of meters in 3 feet = 3\times 0.305 = 0.915\ m

Width of the counter top = 0.915 m

Now we know that;

Area of the counter top can be calculated by multiplying Length of the counter top with width of the counter top.

framing in equation form we get;

Area of the counter top = 5.49\times 0.915 = 5.0233\ m^2

Rounding up to 2 decimals we get;

Area of the counter top =  5.02\ m^2

Hence Area of the counter top is 5.02\ m^2.

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At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

6 0
3 years ago
The equations of a system have the same slopes. What can you determine about the solution of the system of equations?
user100 [1]
One of two things:
-There is no solution because they are parallel lines
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5 0
3 years ago
Solve these problems! Show your work if you would like.
Furkat [3]

Answer:

7. is 2 squared. I didn't show my work but I am very sure that's the answer.

6 0
3 years ago
Please help Need help
Anettt [7]
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where 
m=slope of line
(x0,y0) is a point through which the line passes.

We know that the line passes through A(3,-6), B(1,2)

All options have a slope of -4, so that should not be a problem.  In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.

So we can check which line passes through which point:

a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3)  means that line passes through A(3,-6) => ok

b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
   ****** this equation is not the line passing through A & B *****

c. y=-4x+6  subtract 2 from both sides (to make the y-coordinate 2)
   y-2 = -4x+4, rearrange
   y-2 = -4(x-1)  
   which means that it passes through B(1,2), so ok

d. y-2=-4(x-1)
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Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
   
8 0
2 years ago
Solve for w. <br><br> 1/3w + 5/6w - 2 = -w
Scorpion4ik [409]

Answer: w=\frac{12}{13}

Step-by-step explanation:

To solve for w, we want to isolate the variable.

\frac{1}{3}w +\frac{5}{6}w-2=-w        [add both sides by 2 and w]

\frac{1}{3}w +\frac{5}{6}w+w=2           [convert to same denominator]

\frac{2}{6}w +\frac{5}{6}w+\frac{6}{6} w=2         [add]

\frac{13}{6} w=2                          [multiply both sides by 6/13]

w=\frac{12}{13}

Now we know that w=\frac{12}{13}.

6 0
3 years ago
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