the standard equation of the circle having the given center and radius is
.
Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
T-2(3-2t)=2t+9
t-6+4t=2t+9
5t-6=2t+9
5t-2t=9+6
3t=15
t=15/3
t=5
Hey there, Bulgogi!
The correct answer will be the first one since [I'm assuming] you know that to calculate the percentage of something, it's the amount of that something divided by the total amount but since only 30 students voted [12+18] multiplied by 100.
So, we are calculating the percentage on votes and 12 students voted for Candidate A so our Numerator will be 12 and our Denominator will be the total amount of student who voted, so 30 [or 12+18]
Once put into a fraction, we will get

which would be equals to 2/5 or 0.4. Now we multiply by 100 and we get a total of 40% for Candidate A.
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