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sertanlavr [38]
3 years ago
7

Use the bacteria parable to determine what fraction of the bottle is full at 11:39.

Mathematics
1 answer:
Alinara [238K]3 years ago
4 0

the answer to this question is 500 dimples on a golf ball.

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Jake bought the pizza shown above for lunch, which was cut into four equal slices. What percentage of the pizza did Jake eat if
garri49 [273]
The answer is B ,, if it's cut into 4 slices so it's equal which you would divide 100 by 4 = 25 :)
8 0
3 years ago
Read 2 more answers
At the bottom is a completed addition problem, with all the digits replaced by letters. Every letter represents a single digit a
Rashid [163]

Answer:

T = 5 (H = 7, M = 1); T = 7 (H = 4, M = 2); T = 9 (H = 1, M = 3)

Step-by-step explanation:

We know MH+MH+MH=TM

MH is a two digit number, and TM is also a two digit number.

MH+MH+MH=3*(MH)<100

3M<=9, meaning that M could be 1, 2, or 3.

If M=1, MH+MH+MH=3(10+H)=30+3H=TM=10*T+1

30+3H=10T+1, so 3H must include 1 in one's digit.

The only possibility is that 3H = 21, then H = 7

MH+MH+MH=17+17+17=TM=51, T = 5

If M=2, MH+MH+MH=3(20+H)=60+3H=TM=10T+2

60+3H=10T+2, so 3H must include 2 in one's digit.

The only possibility is 3H = 12, then H = 4

MH+MH+MH=24+24+24=72, T = 7

If M=3, MH+MH+MH=3(30+H)=90+3H=TM=10T+3

90+3H=10T+3, so 3H must include 3 in one's digit.

The only possibility is 3H = 3, then H =1

MH+MH+MH=31+31+31=93, T=9

4 0
3 years ago
Assume that the random variable X is normally distributed with mean u = 45 and standard deviation o = 14.
larisa86 [58]

Answer:

P(57 < X < 69) = 0.1513

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 14

Find P(57 < X < 69):

This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 45}{14}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

X = 57

Z = \frac{X - \mu}{\sigma}

Z = \frac{57 - 45}{14}

Z = 0.86

Z = 0.86 has a pvalue of 0.8051

0.9564 - 0.8051 = 0.1513

P(57 < X < 69) = 0.1513

4 0
3 years ago
Jessica always uses the same ratio of green beads to blue beads when she makes necklaces. The graph shows these equivalent ratio
sveta [45]

Answer:

table 2

Step-by-step explanation:

see attached

7 0
3 years ago
Read 2 more answers
In △ABC point D is the midpoint of
Sergeu [11.5K]

Answer: The area of the triangle ABC is 168 cm square.

Explanation:

Let the area of the triangle ABC be x cm square.

It is given that In △ABC point D is the midpoint of  AB , point E is the midpoint of  BC , and point F is the midpoint of  BE .

As we know that a median of a triangle divides the area of a triangle in two equal parts. Since D is a midpoint of AB and AD is median of triangle ABC. So area of triangle ACD and BCD is half of the area of triangle ABC.

The area of ACD and BCD is \frac{x}{2}.

Since E is a midpoint of BC and DE is median of triangle BCD. So area of triangle BDE and CDE is half of the area of triangle BCD.

The area of BDE and CDE is \frac{x}{4}.

Since F is a midpoint of BE and DF is median of triangle BDE. So area of triangle BDF and DEF is half of the area of triangle BDE.

The area of BDF and DEF is \frac{x}{8}. As shown in below figure.

It is given that the area of △DCF= 63 cm.

From the figure the area of △DCF is,

\frac{x}{4}+ \frac{x}{8}=63

\frac{3x}{8} =63

x=63\times \frac{8}{3}

x=168

Therefore the area of triangle ABC is 168 cm square.

7 0
3 years ago
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