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sergejj [24]
3 years ago
8

If a temperature in degrees Celsius is given as C, finding the sum of 1.8 times C and 32 gives the temperature in degrees Fahren

heit.
The temperature in degrees Fahrenheit is given by , and 40°C is equal to °F.
Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0

Answer:

just wanted to make sure you received my email

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The side lengths of a square was dilated by the scale factor of 4/5. The new area of the square is 64 cm2. Find the original sid
PSYCHO15rus [73]
Solve for side

a = 8 cm

A Area 64 cm^2

Using the formula

A = a^2

a = \sqrt{A}  =  \sqrt{64} = 8cm
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3 years ago
What is the answer to 8 3n/12=13?
Greeley [361]
Does this say 8 × 3n/12=13? I want to be sure so I don't give you the wrong answer.
7 0
3 years ago
HELP ME PLZ WILL MARK BR ASAP
Murljashka [212]

Answer:

the answer is A. 47

Step-by-step explanation:

tanθ = 15/14

the answer for 15/14 comes out to be about 1.0714 and so you put that value into your calculator using the sin^-1 button. it should look something like this sin^-1(1.0714) and press enter and you'll get 46.974 and round will result in 47

3 0
3 years ago
5/6 - ( -1/8)<br> write your answer in simplest form
kupik [55]

Answer: 23/24

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4 0
2 years ago
Emilia and Ferdinand took the same freshman chemistry course: Emilia in the fall, Ferdinand in the spring. Emilia made an 83 on
Wewaii [24]

Answer:

z = \frac{83-76}{8}=0.875

z = \frac{79-65}{12}=1.167

As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Emilia case

Let X the random variable that represent the scores of a test, and we know that

Where \mu=76 and \sigma=8

The z score formula is given by:

z=\frac{x-\mu}{\sigma}

Since Emilia made 83 points we can find the z score like this:

z = \frac{83-76}{8}=0.875

Ferdinand case

Let X the random variable that represent the scores of a test, and we know that

Where \mu=65 and \sigma=12

The z score formula is given by:

z=\frac{x-\mu}{\sigma}

Since Ferdinand made 79 points we can find the z score like this:

z = \frac{79-65}{12}=1.167

As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.

5 0
3 years ago
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