Answer:
the answer is 612 -4n4+6n-5772
The dimension of one side of the stamp was 2 centimeters
Step-by-step explanation:
The formula of the area of any square is A = l², where l is the
length of the side of the square
lance bought a square postage stamp to a mail a card to his cousin
∵ The stamp has 4 square centimeters
∴ The area of the stamp = 4 cm²
∵ The stamp shaped a square
∵ The formula of the area of the square is A = l²
- Equate the formula of the area of the square by the area of the stamp
∴ l² = 4
- Take √ for both sides to find l
∴ 
∴ l = 2 cm
The dimension of one side of the stamp was 2 centimeters
Learn more:
You can learn more about the area of the shapes in brainly.com/question/10677255
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Standard form.
Where m is the slope and n is the point where x=0. Then, you have,
To obtain n use the point they give you,
So n=-7 and then
The answers are as follows:
1. Triangles are often used to build different types of support structures because of its beneficial properties. Triangles is rigid in shape and it has strength. When force is applied to the side of a triangle, it can not shift into another shape, this is because its sides and angles are fixed.
2. The properties of triangle that make it a desirable geometric shape for building support structures is its fixed sides, fixed angles, rigidity and strength. Triangles are the strongest shapes and they are stable. Thus, triangle can be easily fix together to provide strength and stability over a wide area.
3. There are different types of triangles, these include: equilateral triangle, scalene, isosceles, right triangle, obtuse and acute. Of all these triangles, the best triangle is equilateral triangle.
4. Triangle is preferred over other types of polygon because, it is the strongest. The other polygons can be bent into different other forms that are not regular polygon, but a triangle always retains its shape and can not be deformed.
Answer:
y = 3x-15 and y = x-7
Step-by-step explanation:
We are asked to write a system of equations with the solution (4,-3)
It is sufficient if we find two lines passing through this point.
Let us take first line as with slope 3.
Then the equation would be of the form
y-y1 = m(x-x1)
y+3 = 3(x-4)
Or y = 3x-15 is one line
Let second line have slope 1
y+3 = 1(x-4)
y = x-7
Now we have two systems of equations as
y = 3x-15 and y = x-7
