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PSYCHO15rus [73]
3 years ago
12

Solve for K K/2 + 1/2 =3

Mathematics
2 answers:
satela [25.4K]3 years ago
6 0

Answer:

probably maybe 5

Step-by-step explanation:

it looks like you want to multiple 2 to each side to eliminate that denominator. then maybe subtract that 1 away to isolate k. it might equal 5 I'm doing it in my head

Mekhanik [1.2K]3 years ago
6 0

Answer:

k = 5

Step-by-step explanation:

k/2 + 1/2 = 3

k + 1 = 6 (multiplying all the terms with 2)

k=6‐1

k = 5

plz mark me as brainliest

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What is the volume, in cubic inches, of a rectangular prism with a height of 19 inches, a width of 11 inches, and a length of 4
jolli1 [7]

Answer:

836

Step-by-step explanation:

4 times 19 times 11

7 0
3 years ago
The ratio of triangle abc to the corresponding side of similar triangle def is 3:5. the perimeter of triangle def is 48in. what
Vlad1618 [11]
ABC : DEF
3: 5
3 x 9.6 : 5 x 9.6
28.8 : 48
Perimeter of triangle ABC = 28.8 inch
7 0
3 years ago
In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist?
hram777 [196]

Answer:

y will be in every single quadrant

Step-by-step explanation:

So we have the equation y\leq \frac{2}{7} x+1  first we will have to look at the equation. It says that y is less than or equal to \frac{2}{7} x+1 since y is less than \frac{2}{7} x+1 the only place the shaded area where y can be is under the line that is drawn be the equation. When the equation is graphed the y-intercept will be on positive 1 it since slope is rise over run it will look something like the file attached to this. so under the line you can see every single quadrant so that is why it would be that way

5 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
What is close to 3/4? is it 13/26, 11/32, 1/2, or 3/8​
jonny [76]

Answer:

1/2 is the closest at .5

Step-by-step explanation:

13/26 is 1/2

3/8 is . 375

11/32 is .344

3 0
3 years ago
Read 2 more answers
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