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PSYCHO15rus [73]
3 years ago
12

Solve for K K/2 + 1/2 =3

Mathematics
2 answers:
satela [25.4K]3 years ago
6 0

Answer:

probably maybe 5

Step-by-step explanation:

it looks like you want to multiple 2 to each side to eliminate that denominator. then maybe subtract that 1 away to isolate k. it might equal 5 I'm doing it in my head

Mekhanik [1.2K]3 years ago
6 0

Answer:

k = 5

Step-by-step explanation:

k/2 + 1/2 = 3

k + 1 = 6 (multiplying all the terms with 2)

k=6‐1

k = 5

plz mark me as brainliest

You might be interested in
The value of Adam's model railway is $550.
garik1379 [7]

Answer:(c)

Step-by-step explanation:

Given

The initial value of Adam's model is A_o=\$550

the value increases exponentially with the rate of r\%

Time period t=5\ years

Final amount A=\$736

Exponential growth is given by

\Rightarrow A=A_o(1+r)^t

Putting values

\Rightarrow 736=550(1+r)^5\\\\\Rightarrow (1+r)^5=1.338

\Rightarrow 1+r=1.05999\\\Rightarrow r=0.05999\ or\ 5.99\%\approx 6\%

Option (c) is correct

6 0
3 years ago
How to Rewrite 8 + 36 as a product of their GCF and the sum of two factors
siniylev [52]

Answer:

4 (2 + 9)

Step-by-step explanation:

  Given expression:

              8 + 36

The greatest common factor is the highest number that divides a number:

8 and 36 ;

  Factors of 8 : 1,2,4, 8

                  36 : 1, 2, 3, 4, 9, 18, 36

The highest common factor is 4;

  8 + 36  = 4 (2 + 9)

7 0
3 years ago
A bag contains 20 marbles: 12 red, 4 blue, 3 yellow, and 1 green. Arielle takes out 2 marbles. What is the probability that they
Marysya12 [62]

Total number of marbles in the bag =20

Number of blue marbles =4

Now we just want two blue marbles out of four.

Probability of taking out first marble which is blue =4/20

Now after we took out one blue marble , number of blue marbles left are 3.

Probability of taking out second marble which is blue =3/20

Total probability = 4/20 *3/20 = 12/400

So probability of taking out two blue marbles is 0.03 or 12/400.


3 0
3 years ago
On May 1, you sign a $1000 note with simple interest of 8.5% and a maturity date of December 19. You make partial
Lelu [443]

Answer:

The amount to be repaid is $379.26.

Step-by-step explanation:

Period of note from May 1 to December 19 = 233 days

Amount of note or principal = $1,000

Simple interest rate = 8.5%

Maturity date = December 19

Repayments:

June 2 = $475

Nov. 4 =  $200

Total paid $675

Simple interest = $54.26 ($1,000 * 8.5% * 233/365)

Total amount to be repaid = $1,054.26

Total amount repaid =               675.00

Balance to be paid on maturity $379.26

8 0
3 years ago
A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.
baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

5 0
3 years ago
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