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3 years ago

Please help me its hard!

Mathematics

2 answers:

asambeis [7]3 years ago

7 0

Answer:

1200

Step-by-step explanation:

Find the width and the height show in the picture then use the formula Area = length X height

The width is 40 and the height is 30. Therefore Multiply it together and get 1200

It may not be the answer!

dolphi86 [110]3 years ago

3 0

Answer:

600

Step-by-step explanation:

Consider ABC and ACD as two triangles. And AC as a base to both of them

so,

AC = AO + OC

= 15 + 25

= 40

Now the area of ABC =

$\frac{1}{2}\times AC\times OB\\= \frac{1}{2}\times 40 \times 10\\= 200$

In the same way, the area of ACD =

$\frac{1}{2}\times AC\times OD\\= \frac{1}{2}\times 40 \times 20\\= 400$

Both added together 400 + 200 = 600

You might be interested in

Are of quadrilateral

koban [17]

Answer:

Area of Quadrilateral = 289.57 sq.cm

Step-by-step explanation:

First of all, let us understand what is a Quadrilateral?

A quadrilateral is a polygon with four sides. A quadrilateral is a closed two-dimensional figure formed by joining the four points among which three points are non-collinear points.

Given,

Length of sides :

AB = 7.5 cm

BC = 11.7 cm

CD = 15.6 cm

AD = 18 cm

and given , the Angle between BCD is 90 degrees and the angle between BAD is 90 degrees.

It implies that the TRAINGLES BCD and BAD are Right angled triangles

So, the length of BD can be found using Pythagorean theorem

Pythagorean theorem, the well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)—or, in familiar algebraic notation, a2 + b2 = c2.

From the Triangle of BCD,

a= BC

b=CD and

c= BD

Therefore, The length of BD =

c= $\sqrt[2]{(11.7^{2})+(15.6 x^{2}) }$

c = $\sqrt{380.25}$

c = 19.5 cm

Hence, c= BD=19.5 cm

Now, Area of Quadrilateral =

1/2*(diagonal)*(sum of height of two triangles)

Here, Diagonal = Length of BD = 19.5 cm

Height (h1) = BC = 11.7 cm

Height ( h2) = AD = 18 cm

Therefore, Area = 1/2*19.5*(11.7+18)

= 289.57 sq.cm

Refer more about Area at below link:

https://brainly.in/question/2466686

#SPJ10

5 0

2 years ago

If (3). write the following vectors in column vector form:

Art [367]

Answer:

see explanation

Step-by-step explanation:

Given

a = $\left[\begin{array}{ccc}3\\2\\\end{array}\right]$

To obtain -3a multiply each of the elements of a by -3

3a = $\left[\begin{array}{ccc}-3(3)\\-3(2)\\\end{array}\right]$ = $\left[\begin{array}{ccc}-9\\-6\\\end{array}\right]$

To obtain 1.5a multiply each element by 1.5

1.5a = $\left[\begin{array}{ccc}1.5(3)\\1.5(2)\\\end{array}\right]$ = $\left[\begin{array}{ccc}4.5\\3\\\end{array}\right]$

8 0

3 years ago

If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.

Sophie [7]

There's no if about it,

$f(x)=x^3+3x^2-x-3
$

has a zero $f(1)=0$ so $x-1$ is a factor. That's the special case of the Remainder Theorem; since $f(1)=0$ we'll get a remainder of zero when we divide $f(x)$ by $x-1.$

At this point we can just divide or we can try more little numbers in the function. It doesn't take too long to discover $f(-1)=0$ too, so $x+1$ is a factor too by the remainder theorem. I can find the third zero as well; but let's say that's out of range for most folks.

So far we have

$x^3+3x^2-x-3 = (x-1)(x+1)(x-r)$

where $r$ is the zero we haven't guessed yet. Again we could divide $f(x)$ by $(x-1)(x+1)=x^2-1$ but just looking at the constant term we must have

$-3 = -1 (1)(-r) = r$

so

$x^3+3x^2-x-3 = (x-1)(x+1)(x+3)$

We check $f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark$

We usually talk about the zeros of a function and the roots of an equation; here we have a function $f(x)$ whose zeros are

$x=1, x=-1, x=-3$

8 0

2 years ago

Read 2 more answers

Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths

kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment

Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13