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Olin [163]
2 years ago
11

The length of a rectangle is four more than three times its width. the area of the rectangle is 25. write an algebraic model for

this situation. solve the equation to find the dimensions of the rectangle.
Mathematics
1 answer:
Dafna11 [192]2 years ago
4 0

width (w) = w

Length (L) = 3w + 4

Area (A) = L x w

25 = (3w + 4)w

25 = 3w² + 4w

0 = 3w² + 4w - 25

w = \frac{-2 +/-\sqrt{79} }{3}

w ≈ 2.3, w ≈ -3.6 (width cannot be negative!)

w ≈ 2.3

Length (L) = 3w + 4 = 3(2.3) + 4 = 6.9 + 4 = 10.9

Answer: width=2.3, Length=10.9

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Step-by-step explanation:

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An equivalent form of the  given compound inequality −44 > −2x − 8 ≥ −8 is  −44 > −2x − 8 and −2x − 8 ≥ −8

Step-by-step explanation:

Given a compound inequality −44 > −2x − 8 ≥ −8

We have to write  an equivalent form of compound inequality.

Compound inequality  consists of two inequalities joined together and the solution is the intersection of each inequality.

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Thus, An equivalent form of the  given compound inequality −44 > −2x − 8 ≥ −8 is  −44 > −2x − 8 and −2x − 8 ≥ −8

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Answer:

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