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sammy [17]
3 years ago
10

What is the area? 3 in 2 in 4 in

Mathematics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

24

Step-by-step explanation:

because to find the area you multiply them all together, 3x2x4

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Okay.
murzikaleks [220]
You would need 105 of sodium I found how much increase there was from 30 to 75 by doing 75/30 which is 2.5 that means the new amount of sodium would be 2.5 times 42 which is 105. You could also set up ratios and cross multiply like the picture I sent

8 0
3 years ago
Does anyone know how to do this ?
goldenfox [79]

Answer: D) 32

Step-by-step explanation:

The area of a parallelogram equals its base times its height. Substitute the base and area into this formula to solve for the height:

A=bh

40=(5)(h)

h=8

If ABCD is a parallelogram, opposite sides are parallel, so AB is parallel to DC. If AB is parallel to DC, EB is parallel to DC. Since EB is parallel to DC, quadrilateral EBCD has at least one pair of parallel sides, making it a trapezoid. The area of a trapezoid is equal to \frac{h(b_{1}+b_{2})  }{2} where h is the height, b_{1} is one base, and b_{2} is the other base. Plug the necessary values into the formula:

A=\frac{h(b_{1}+b_{2})  }{2}

b_{1} =AB-AE\\DC=AB\\b_{1} =DC-AE\\b_{1} =5-2\\b_{1} =3

b_{2} =5

h=8

A=\frac{8(3+5)}{2}

A=32

The answer is D) 32.

6 0
2 years ago
What is the LCM of 5 and 12
Virty [35]
60. The answer is 60
3 0
3 years ago
What is the value of t in the following equation?<br><br> t + 14 = 2712
Solnce55 [7]

Answer:

2698

Step-by-step explanation:

2712-14

4 0
2 years ago
Read 2 more answers
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
2 years ago
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