Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
It’s a positive slope, constant slope, and increasing function. Because it’s a straight line going diagonally to the top right, you know the slope is positive, constant, and the function is positive.
Answer:
There are infinite number of triangles that could be achieved with those angles.
To picture this, we only have to imagine a triangle that is either smaller or bigger than the one at hand.
Tracing a series of paralell lines (which guarantee that the angles are being kept), we can draw triangles for infinite values of x,y and z.
6 because the 36 is r² where r is the radius, r² = 36; we have to isolate the r so it's by its self, so square root both sides, r = 6
