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DanielleElmas [232]
2 years ago
11

sandra used 2 jars of beads to make 16 necklaces how many jars of beads would she need to make 192 neclaces

Mathematics
2 answers:
garik1379 [7]2 years ago
4 0

Answer:

24 Jars

Step-by-step explanation:

Do 16/2, which gives you eight for every necklace. Then do 192/8 which would give you 24. So, she would need 24 jars for 192 necklaces.

Katena32 [7]2 years ago
3 0

Answer:

16÷2=8

8÷192=24

its 24

all you have to do is divide the 16 and 2 to see how many is in each jar and how much they have done then just just divide that number with 192.

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Answer:

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4 0
3 years ago
At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

8 0
3 years ago
What is a equivalent expression for 3y+y+4+y
kherson [118]

an equivalent expression is 5y+4

there is 3y which is y+y+y

so you have y+y+y+y+4+y

there are 5 y so it is 5y

then you have +4

5y+4

7 0
3 years ago
Can someone please help me with this question please please help me I really really need help please.
harina [27]

Answer:

1st : neither linear nor nonlinear

2nd: nonlinear

3rd: linear

4th: both linear and nonlinear

4 0
3 years ago
The average age of online consumers a few years ago was 24.1 years. As older individuals gain confidence with the​ Internet, it
love history [14]

Answer:

The correct option is (C).

Step-by-step explanation:

A null hypothesis is a sort of hypothesis used in statistics that intends that no statistical significance exists in a set of given observations.  

It is a hypothesis of no difference.

It is typically the hypothesis a scientist or experimenter will attempt to refute or discard. It is denoted by H₀.

Whereas the alternative hypothesis is a contradicting statement tot he null hypothesis. It is denoted by Hₐ.

In this case we need to test whether the average age of online consumers has increased or not.

From previous data we know that the average age of online consumers a few years ago was 24.1 years.

A one-sample mean test can be used to determine whether the mean age has increased or not.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The average age of online consumers is 24.1 years, i.e. <em>μ</em> = 24.1.

<em>Hₐ</em>: The average age of online consumers is more than 24.1 years, i.e. <em>μ</em> > 24.1.

Thus, the correct option is (C).

6 0
3 years ago
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