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3 years ago

Is this right? Please check and tell me the answer fast

Mathematics

2 answers:

Goryan [66]3 years ago

7 0

Yes it is correct, I've done the maths myself as wlel

shusha [124]3 years ago

7 0

Check your values again $\bf \begin{array}{ccccccc}
x&|&-2&-1&0&1&2
\\ \quad \\

f(x)&|&-(-2)^2+3&-(-1)^2+3&-(0)^2+3&-(1)^2+3&-(2)^2+3
\end{array}$

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Solve 40 = 20 + 2(x-3)

Rom4ik [11]

Answer: 19x

Step-by-step explanation:Because if you add 22 and 2 and minus 3 and add the x you get your answer 19x

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3 years ago

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What are the answers to 2 and 4

Pavel [41]

2. y = -4x + 1 so slope m = -4

passing thru (3,-1)
y = mx + b
-1 = -4(3) + b
-1 = -12 + b
11 = b or b = 11

answer:
equation: y = -4x + 11

4.
answer is a. -2, 1/2 opposite reciprocal

b. 1/4 , 4 ..... only reciprocal
c. 5, -5..........only opposite

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3 years ago

The area of a square ice rink is 400 yd.². What is the perimeter of the rink in yards

MakcuM [25]

Answer:

80 yd^2

Step-by-step explanation:

Since the formula for squares is s^2, we can use this to set up an equation, which is

s^2=400

If we square root this, we get

s=20

The perimeter formula for a square is 4s, so if we plug in, we end up with 80 yd^2

8 0

3 years ago

4 divide by the square root of 2

xxTIMURxx [149]

Answer: 2.82842712475

Step-by-step explanation:

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3 years ago

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What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$