Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
The answer is 14. The two lower angles are 50 each 100 total and so the top angle must equal 80. If you set it equal to 80 you get 14.
If you square 3, you get 9, and if you "take the square root of 9", you get 3
Answer:
The answer is 8.5
Step-by-step explanation:
Just list all the numbers and cross them out one by one.
