Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer: f(x)=125g+50
Explanation: He is charging $125 for each gold piece so you would multiply “g” and 125.
You would add 50 as a one time fee so you add 50.
Answer:
Following are the responses to these questions:
Step-by-step explanation:
In point a:
Please find the graph file in the attachment.
In point b:
This information is interesting for us, because we inform us about an important disease outbreak in such days and how the pandemic impacts major global communities like London as well as how the pattern in the recorded cases is increasing and decreasing.
In point c:
The data are sorted: 551, 1683, 3194, 4053, 4079, 5842, 5868
Mean
Median proves middle value or class so if ascending data is arranged = 4th term = 4053
A mode is of max 
Range It is also the difference between max and min values which indicates the overall distribution range 
The standard deviation
