What is the value of 503492 and 26475

The point (–7, –3) is located in which quadrant?

Dmitry_Shevchenko [17]

Answer:

Quadrant III

Step-by-step explanation:

8 0

2 years ago

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In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o

ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = $\frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}$

X = 0.13

s = $\sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }$

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for $t_{6,0.005}$ is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = $t_{6,0.005}$ . $\frac{s}{\sqrt{N} }$

E = 3.707. $\frac{0.029}{\sqrt{7} }$

E = 0.041

The interval will be:

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0

3 years ago

Subtract. Write your answer as a mixed number in simplest form.<br><br> 8 1/8 - 3 3/8

polet [3.4K]

Therefore, 4 3/4 is your answer

8 0

2 years ago

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In science class, the students observed 24 of the 300 frogs from the local aquarium. If 6 of the frogs observed had spots, how m

Alona [7]

Answer:

225 frogs

Step-by-step explanation:

Total population of frogs = 300 frogs.

Observed population of frogs = 24

6 of the 24 observed frogs had spots

Which means , the number of frogs that did not have spots = 24 - 6 = 18 frogs.

We were told to find how many of the total population can be predicted to NOT have spots. We would form a proportion.

If 24 frogs = 18 frogs with no spots

300 frogs = Y

Cross multiply

24Y = 300 × 18

Y = (300 × 18) ÷ 24

Y = 5400 ÷ 24

Y = 225 frogs.

This means out of 300 frogs, 225 frogs do not have spots.

Therefore, the total population that can be predicted to NOT have spots is 225 frogs.

the total population can be predicted to NOT have spots

3 0

2 years ago

If three quarters of a number decreased by twenty is equal to eighty two, what is that number?

Studentka2010 [4]

A number is :

$x$

_________________________________

Three quarters of it means :

$\frac{3}{4}x \\$

_________________________________

Decrease by 20 means :

$\frac{3}{4}x - 20 \\$

_________________________________

Equals to 82 means :

$\frac{3}{4}x - 20 = 82 \\$

_________________________________

What is that number ?

x asked so we must solve the above equation for x.

Let's do it....

$\frac{3}{4}x - 20 = 82 \\$

Plus sides 20

$\frac{3}{4}x = 82 + 20 \\$

$\frac{3}{4}x = 102 \\$

Multiply sides by 4

$3x = 102 \times 4$

Divided sides by 3

$x = \frac{102 \times 4}{3} \\$

$x = \frac{102}{3} \times 4 \\$

Simplify

$x = 34 \times 4$

$x = 136$

So that number is 136 .

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

5 0

3 years ago