Please help! 10 points

Paha777 [63]

Answer:

Je ne parle pas français donc j'utilise un traducteur. J'espère qu'il n'y a pas trop d'erreurs. Le frère de Maurice a dépensé 5,20 $ et Maurice 20,80 $

Step-by-step explanation:

7 0

3 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

║

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

⊥

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

║

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

The design of a microchip has the scale 40:1. The length of the design is 18cm, find the actual length of the micro chip?

zimovet [89]

Answer:

0.45 cm

Step-by-step explanation:

Actual length of the micro chip

$= \frac{1}{40} \times 18 \\ \\ =0.45 \: cm$

4 0

3 years ago

Find the first 3 iterations of the function here: g(n) = 3x if you have an initial value of 2.

Tom [10]

1st it: g(2)=3(2)=6 || 2nd it: g^2(2)=3(6)=18 || 3rd it: g^3(2)=3(18)=54

4 0

3 years ago

PLZ HURRY!!!!!!!!!!!!! Simplify. −4x^2(5x^4−3x^2+x−2)

Simora [160]

$\bold{Answer}$

$\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}$

$\bold{Explanation}$

$\bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}$

$\bold{------------------}$

$\bold{Distribute \ Parenthesis}$

$\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}$

$\bold{Apply \ Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}$

$\bold{-4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2}$

$\bold{Simplify \ -4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2: \ -20x^6+12x^4-4x^3+8x^2}$

$\bold{-20x^6+12x^4-4x^3+8x^2}$

$\boxed{\bold{Eclipsed}}$

5 0

3 years ago