The most likely type of instruction that was executed by the CPU is: a jump instruction.
<h3>What is a CPU?</h3>
A central processing unit (CPU) can be defined as the main components of a computer because it acts as the brain of a computer and does all the processing and logical control.
This ultimately implies that, a central processing unit (CPU) is typically used by a computer to execute an instruction or set of instructions when powered on.
<h3>What is a
jump instruction?</h3>
In Computer technology, a jump instruction specifies an offset to a new place in the program sequence when processing an instruction or set of instructions in a computer.
Read more on CPU here: brainly.com/question/5430107
Answer:
Since the computer accepts raw data as input and converts into information by means of data processing
Explanation:
helping!!!
Answer:
1.
class TIME
{
int hour , min , sec ;
public :
TIME()
{
hour=min=sec=0;
}
TIME( int h , int m , int s )
{
hour = h;
min = m;
sec = s;
}
void change ( int Hour)
{
hour = Hour;
}
void stdtime()
{
if(hour>12)
cout<<"The Standard time is"<<(hour-12)<<":"<<min<<":"<<sec<<"P.M\n";
else
cout<<"The Standard time is"<<hour<<":"<<min<<":"<<sec<<"A.M\n";
}
void miltime()
{
cout<<"The Military time is"<<hour<<":"<<min<<":"<<sec<<" hours\n";
}
};
void main()
{
TIME A , B(13,25,30);
A .stdtime();
A.change(23);
A.miltime();
B.stdtime();
B.change(9);
B.miltime();
}
2.
class elevator
{
int CurrentFloor;
int GoingUp;
int GoingDown;
public:
elevator()
{
CurrentFloor=0;
GoingUp=1;
GoingDown=-1;
}
elevator(int floor)
{
CurrentFloor=floor;
GoingUp=1;
GoingDown=-1;
}
void goUp(int y)
{
if( CurrentFloor>3)
cout<<"\nNO MORE FLOORS\n";
else
CurrentFloor=CurrentFloor+y*GoingUp;
}
void goDown(int x)
{
if(CurrentFloor<0)
cout<<"\nNO MORE FLOORS";
else
CurrentFloor=CurrentFloor+x*GoingDown;
}
};
void main()
{
elevator A(1);
A.goUp(1);
A.goUp(1);
A.goUp(1);
A.goDown(1);
A.goDown(1);
}
Yes, mobile devices have to work in limited screen space.
Answer:
START LOOP FOR EACH EMPLOYEE:
INPUT employee’s name, hourly rate of pay, number of hours worked, overtime pay rate, payroll deductions, tax rate
SET gross pay = (hourly rate of pay x *weekly hours) + (overtime pay rate x (number of hours worked - *weekly hours))
PRINT gross pay
SET net pay = gross pay - (payroll deductions + (gross pay * tax rate/100 ))
PRINT net pay
END LOOP
* weekly hours (how many hours an employee needs to work to earn overtime pay rate) is not given in the question
Explanation:
Create a loop that iterates for each employee
Inside the loop, ask for name, hourly rate, number of hours worked, overtime pay rate, payroll deductions, tax rate. Calculate the gross pay and print it. Calculate the net pay and print it
