(-2m + 5n)²
(-2m + 5n) (-2m + 5n)
-2m(-2m + 5n) + 5n(-2m + 5n)
4m² - 10mn - 10mn + 25n²
4m² - 20mn + 25n²
4m²⇒ -2m * -2m
-20mn ⇒ 2(-2m)(5n)
25n² ⇒ 5n * 5n
<span>C. 4m² − 20mn + 25n²; a perfect square trinomial</span>
We need to find the circumference of the orbit of the spacecraft. Let's first determine the radius of the orbit. From the planet's center, the spacecraft is 3,390 + 365 km away = 3,755 km.
Circumference = 2πr
C=2(π)(3755 km)
C≈ 23593 km
Answer:
im confused but if i had to guess without any additional info i would think you mean 2m and m=5 so 2m=10 lmk if that's not what you meant
Step-by-step explanation:
14 is the answerrrrrrrrrrrrr
It would be -4z
(: need more characters
