B

g A jacket regularly sells for $135.00. The sale price is $60.75. Find the percent decrease of the sale price from the regular p

Alenkasestr [34]

Answer:

55%

the percent decrease of the sale price from the regular price is 55%

Step-by-step explanation:

Percentage decrease is the percentage change in the sales price (regular and new)

Percentage decrease %∆P = ∆P/Pr × 100%

∆P = change in sales price = $135 - $60.75

Pr = regular price = $135

Substituting the values;

%∆P = (135-60.75)/135 × 100%

%∆P = 55%

the percent decrease of the sale price from the regular price is 55%

5 0

3 years ago

What are the coordinates of the midpoint between the points (-4, -9) and (-8, -5)? Select the best answer from the choices provi

OLga [1]

B). (-6,-7)

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

8 0

3 years ago

2. Find the missing angle x. 155° 60° X

Kryger [21]

Answer:

exterior angle property use ...

the exterior angle of an angle is equal to sum of rest 2 interior angles in a triangle

155 = 60 + x

x = 155 - 60 = 95

8 0

3 years ago

Which relationship is always true for the angles x, y, and z of triangle ABC? A triangle is shown with a leg extending past the

nlexa [21]

Answer:

y+z=x

Step-by-step explanation:

we know that

The Exterior Angle Property of a Triangle states that the measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles

In this problem

Angle y and angle z are interior angles of triangle ABC and angle x is a exterior angle of triangle ABC

therefore

Applying the Exterior Angle Property of a Triangle

y+z=x

4 0

3 years ago

A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran

Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0

3 years ago