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Lina20 [59]
2 years ago
9

Solve for the variable K. m/k=x

Mathematics
2 answers:
snow_tiger [21]2 years ago
7 0

Answer:

\frac{m}{k}  = x \\ \\ \frac{1}{k}  =  \frac{x}{m} \\ \\ k =  \frac{m}{x}

Hope it helps

Sladkaya [172]2 years ago
5 0

Answer:

\frac{m}{k}  = x \\  \\ kx = m \\  \\ k =  \frac{m}{x}

I hope I helped you^_^

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I need this done super fast help!!!! And it has 7 parts so step by step please
bagirrra123 [75]

Answer:

177 and 178

Step-by-step explanation:

First, the expression for the 2nd mile marker is x+1.

Now, you add x and x + 1 together to get 2x + 1

Next, make 2x + 1 equal to 355

Now subtract 1 and then divide by two on both sides to get x = 177.

This means that the first mile marker is 177 and the next is 178.

4 0
3 years ago
If the mass of a proton is 2.53 x 10^-37 gram, what is the mass of 1,000 protons
Dmitrij [34]
We can solve this problem by the rule of three.

1000 protons=10³ protons

1 proton------------------2.53*10⁻³⁷g
10³ protons----------   x

x=(10³ protons  *   2.53*10⁻³⁷) / 1 proton=2.53*10⁻³⁷⁺³ protons=
=2.53*10⁻³⁴ protons

answer: 2.53*10⁻³⁴ protons
3 0
3 years ago
If f(x)=5x, what is f^-1(x)?
Georgia [21]

Answer:

first thing to do is get up from your sit and go cry because that question is to hard

5 0
3 years ago
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
2 years ago
Annie had 16 balloons she shares them equally with Connie how many balloons does each girl have now?
Marina CMI [18]
Each girl gets 8 ballons
8 0
3 years ago
Read 2 more answers
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