x²-6x =7
First we have get rid of that 7 from the right side and move it to the left side. To move 7 to the left side, we have to subtract 7 from both sides.
x²-6x-7= 7-7
x²-6x-7 = 0
To make this equation a perfect square, first we have to check the x term. Here -6x given. We have to divide the co-efficient of x by 2, and then we have to add the square of it.
The co-efficient of x is -6 here. Dividing it by 2, we will get -6/2 = -3.
We will have to add (-3)² here. (-3)² is 9. So in the place of -7, we have to make 9, to make the equation a perfect square.
9-(-7) = 9+7 = 16
So by adding 16 to the left side, we can make the equation a perfect square.
x²-6x-7+16 =0
x²-6x+9 =0
x²-6x+(-3)² =0
(x-3)² =0
Split it into three rectangles, find the area of each one and add them together. You can split it multiple ways but the way I did it, you would end up with this: 10*2+2*2+2*2
B. -5
The two straight lines are parallel, and the angles are at the same places (below and to the right of the diagonal line). The two angles must be the same, and to get 65 from x + 70, x has to be -5.
Answer:
-71-10n
Step-by-step explanation:
-4(11+4n)-3(-2n+9)
-44-16n+6n-27
-44-27-10n
-71-10n
