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Sonbull [250]
3 years ago
12

76degrees faherheit = what in Celsius?​

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

24.4444

Step-by-step explanation:

76 degrees faherheit = 24.4444 degrees Celsius

(76°F − 32) × 5/9 = 24.444°C

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Alicia has invented a new app that two companies are interested in purchasing for a 2-year contract. Company A is offering $10,0
Fantom [35]

Answer:

Month 8

In this month Company B's plan will pay $64,000 versus $45,000 from Company A.

Step-by-step explanation:

Start by calculating the monthly payments for both plans.

Month - Company A - Company B

1      $10,000        $500

2      $15,000       $1,000

3      $20,000       $2,000

4      $25,000       $4,000

5      $30,000       $8,000

6      $35,000       $16,000

7      $40,000      $32,000

8      $45,000      $64,000

9      $50,000     $128,000

10      $55,000     $256,000

11 $60,000 $512,000

12 $65,000 $1,024,000

13 $70,000 $2,048,000

14 $75,000 $4,096,000

15 $80,000 $8,192,000

16 $85,000 $16,384,000

17 $90,000 $32,768,000

18 $95,000 $65,536,000

19 $100,000 $131,072,000

20 $105,000 $262,144,000

21 $110,000 $524,288,000

22 $115,000 $1,048,576,000

23 $120,000 $2,097,152,000

24 $125,000 $4,194,304,000


7 0
4 years ago
Read 2 more answers
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
4 years ago
Use a spinner to find the theoretical probability of spinning an even number. What is the theoretical probability of spinning an
stiv31 [10]

Answer:

4/8

Step-by-step explanation:

There are half even and half odd numbers on a spinner so it is 1/2 of 8 which is 4. Then you put the 4 over 8 to gain your probability.

7 0
3 years ago
Read 2 more answers
On Monday, it snowed 30 inches in 16 hours. On Thursday, it snowed 21 inches in 6 hours. On which day did it snow at a greater r
nevsk [136]

Answer: Thursday

Step-by-step explanation:

I think this answer is correct because, On Monday it says it snowed 30 inches for 16 hours, so we divide 30 by  16 and we get 1.875. But for Thursday it snowed 21 for 6 hours, so we divide 21 by 6 and that equals 3.5. So on Monday it snowed 1.875 snow per hour and Thursday it snowed 3.5 snow per hour. So the answer is Thursay!

Hope This Helps!

5 0
3 years ago
Read 2 more answers
Find integrate (1/(xsqrt(1+(lnx)^2)),1,e,x) ...?
prohojiy [21]
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as 

<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>

<span>Next, complete the square. </span>

<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>

<span>Also, for the x in the numerator </span>

<span>x = x + 1/2 - 1/2. </span>

<span>So </span>

<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>

<span>Integrate term by term to get </span>

<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>

<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>

<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>

<span>= 2 √(x) ln(x) - √(x) + C. </span>

<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>

<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>

<span>= arctan(e^x) + C.</span>
4 0
3 years ago
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