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3 years ago

Help me out here guys

1 answer:

3 0

D.

f(x) can be written as (x+2)(x-2)(x-1)
by using difference of two squares to expand x^2 - 4 whch yields 3 x intercepts

similarly, k(x) can be written as
x(x+5)(x-5) which also yields 3
x intercepts (0,-5, and 5)

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The sum of two numbers is 2. The sum of three times the larger and twice the smaller is 14. Find the numbers.

anzhelika [568]

For this case we have to:

x: Be the variable that represents the largest number

y: Be the variable that represents the smallest number

We propose a system of equations:

$x + y = 2\\3x + 2y = 14$

From the first equation we have to:

$x = 2-y$

Substituting in the second equation:

$3 (2-y) + 2y = 14\\6-3y + 2y = 14\\6-y = 14\\-y = 14-6\\-y = 8\\y = -8$

We look for the value of "x":

$x = 2 - (- 8)\\x = 2 + 8\\x = 10$

Answer: $x = 10\\y = -8$

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4 years ago

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3 years ago

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stepan [7]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the value of X! Please help!

nydimaria [60]

ANSWER

$x = 8 \sqrt{3}$

EXPLANATION

${h}^{2} = {y}^{2} + {4}^{2}$
This implies that,

${h}^{2} = {y}^{2} + 16...eqn1$

Also,

${h}^{2} + {x}^{2} = {16}^{2} ...eqn2$

And

${y}^{2} + {12}^{2} = {x}^{2}$

${y}^{2}={x}^{2} - 144 ...eqn3$

Put equation 1 into equation 2.

This will give us,

${y}^{2} + 16 + {x}^{2} = {16}^{2}$

${y}^{2} +{x}^{2} = {16}^{2} - 16$

${y}^{2} +{x}^{2} =16 ( 16 - 1)$

${y}^{2} +{x}^{2} =240...eqn4$

We put equation 3 into equation 4,

${x}^{2} - 144+{x}^{2} =240$

We simplify to get,

$2 {x}^{2} = 384$

${x}^{2} = 192$

$x = \sqrt{192}$

$x = 8 \sqrt{3}$

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3 years ago