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frozen [14]
3 years ago
8

Help me out here guys

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
D.

f(x) can be written as (x+2)(x-2)(x-1)
by using difference of two squares to expand x^2 - 4 whch yields 3 x intercepts

similarly, k(x) can be written as
x(x+5)(x-5) which also yields 3
x intercepts (0,-5, and 5)
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The sum of two numbers is 2. The sum of three times the larger and twice the smaller is 14. Find the numbers.
anzhelika [568]

For this case we have to:

x: Be the variable that represents the largest number

y: Be the variable that represents the smallest number

We propose a system of equations:

x + y = 2\\3x + 2y = 14

From the first equation we have to:

x = 2-y

Substituting in the second equation:

3 (2-y) + 2y = 14\\6-3y + 2y = 14\\6-y = 14\\-y = 14-6\\-y = 8\\y = -8

We look for the value of "x":

x = 2 - (- 8)\\x = 2 + 8\\x = 10

Answer:x = 10\\y = -8

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Step-by-step explanation:

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Read 2 more answers
Find the value of X! Please help!
nydimaria [60]
ANSWER

x = 8 \sqrt{3}

EXPLANATION

{h}^{2} = {y}^{2} + {4}^{2}
This implies that,

{h}^{2} = {y}^{2} + 16...eqn1

Also,

{h}^{2} + {x}^{2} = {16}^{2} ...eqn2

And

{y}^{2} + {12}^{2} = {x}^{2}

{y}^{2}={x}^{2} - 144 ...eqn3

Put equation 1 into equation 2.

This will give us,

{y}^{2} + 16 + {x}^{2} = {16}^{2}

{y}^{2} +{x}^{2} = {16}^{2} - 16

{y}^{2} +{x}^{2} =16 ( 16 - 1)

{y}^{2} +{x}^{2} =240...eqn4

We put equation 3 into equation 4,

{x}^{2} - 144+{x}^{2} =240

We simplify to get,

2 {x}^{2} = 384

{x}^{2} = 192

x = \sqrt{192}

x = 8 \sqrt{3}
4 0
3 years ago
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