Answer:
39 and 65
Step-by-step explanation:
the ratio of the two numbers is 3 : 5
sum the parts of the ratio, 3 + 5 = 8 parts
divide the sum by 8 to find the value of one part of the ratio
104 ÷ 8 = 13 ← value of 1 part of the ratio , then
3 parts = 3 × 13 = 39
5 parts = 5 × 13 = 65
the two numbers are 39 and 65
Answer:
I disagree . I don’t agree because if you have 25 bags with 20 braclets in each then you would just waste So many bags because you can fit 500 bracelets in those bags all together.
Step-by-step explanation:
HOPE THIS HELPS
PLZZ MARK BRAINLIEST
3/5 cannot be simplified into a smaller fraction.
(32 + 18 + 13) / 3 = b
/ is divided by
you would add the boxes together and then divide them equally into the 3 displays
Since ![[0,4]=[0,1]\cup(1,4]](https://tex.z-dn.net/?f=%5B0%2C4%5D%3D%5B0%2C1%5D%5Ccup%281%2C4%5D)
, we can rewrite the integral as
Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:
Both integrals are quite immediate: you only need to use the power rule
to get
![\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E11-3t%5E2%5C%3Bdt%20%3D%20%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%2C%5Cquad%20%5Cint_1%5E4%202t%5C%3B%20dt%20%3D%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4)
Now we only need to evaluate the antiderivatives:
![\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15](https://tex.z-dn.net/?f=%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%20%3D%201-1%5E3%3D0%2C%5Cquad%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4%20%3D%204%5E2-1%5E2%3D15)
So, the final answer is 15.
