Answer:
The player shooting 390/434 is a free throw percentage of 89.86%. We can now estimate his probability of making the next 2 shots as (.8986)^2 = .8075.
So now to find the expected value, you just need to find the value of each possible outcomes (he makes both or he doesn't).
P(makes both) * (Value when you win) + P(misses both) * (value when you lose)
.8075 * $40 + (1-.8075)*(-$169)
32.2 - 32.53
= -$.23
For the second part, you already know the expected value of each possible game. So now you just need to multiply that by 588 to get your expected loss on 588 games.
D=100:
g=12-1/25(100)
g=12-4
g=8, d=100
d=200:
g =12-1/25(200)
g=12-8
g=4, d=200
d=300:
g =12-1/25(300)
g=12- 12
g=0, d=300
I believe the answer would be 1086.4
Please give a like if I’m right and tell me in the comments if I’m wrong.
Hope this helped :)
Answer:
the third one from the top
Step-by-step explanation: