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JulijaS [17]
2 years ago
8

What is 1086.3961 rounded to the nearest square foot?

Mathematics
1 answer:
Katen [24]2 years ago
3 0
I believe the answer would be 1086.4

Please give a like if I’m right and tell me in the comments if I’m wrong.
Hope this helped :)
You might be interested in
185g shared to the ratio of 2:3
Yuliya22 [10]
The smaller share is 2/(2+3)*185 g = 74 g.
The larger share is 185 -74 g = 111 g.
8 0
3 years ago
The scale for a model house is 1:12
guapka [62]

Answer:

here's what I got from wikipedia (i dont like taking of other's brain skills :/ )

Step-by-step explanation:

<em>1:12 scale is a traditional scale (ratio) for models and miniatures, in which 12 units (such as inches or centimeters) on the original is represented by one unit on the model. Depending on application, the scale is also called one-inch scale (since 1 inch equals 1 foot)</em>

<em>hope this helps you :)</em>

5 0
3 years ago
Read 2 more answers
PLS HELP Find the m∠RLU.<br> A. 10º<br> B. 6º<br> C. 25º<br> D. 50º
balandron [24]

Step-by-step explanation:

6n-10=50

6n=60

n=10

rlu=6n-10

=6×10-10

=60-10

50

8 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
3 = –(–y + 6)<br> a. –9<br> b. –3<br> c. 3<br> d. 9
Vlad1618 [11]
3 = -(-y + 6)

First, simplify brackets. / Your problem should look like: 3 = y - 6
Second, add 6 to both sides. / Your problem should look like: 3 + 6 = y
Third, simplify 3 + 6 to 9. / Your problem should look like: 9 = y
Fourth, switch sides. / Your problem should look like: y = 9

The answer is D) 9.

7 0
3 years ago
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