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3 years ago

Can u plz help me plz don’t guess

Mathematics

1 answer:

OLga [1]3 years ago

4 0

Answer:

B) Checkers Club

Step-by-step explanation:

The spread is the difference between the minimum and the maximum. Those extreme values are indicated by the dots at the ends of the "whiskers" in the "box and whisker" plot.

Chess club extends from 8 to 18, so the spread is 18 -8 = 10.

Checkers club extends from 6 to 17, so the spread is 17 -6 = 11. This is a greater value than 10.

Checkers club has the greater spread.

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Answer both and i will give brianlist

ki77a [65]

Answer:

1. Perpendicular

2. y=5x+7

Step-by-step explanation:

brainliest please?

7 0

3 years ago

Which number belongs to the set of rational numbers and the set of integers?

professor190 [17]

-12 is an integer number, and you can write it as {-12}{1}

7.3 is a rational number, and you can write is as {73}{10}

0.41 is a rational number, and you can write is as {41}{100}

6 is a whole number, and you can write it as {6}{1}

3 1/2 is a rational number, and you can write is as

3+{1}{2}={6}{2}+{1}{2}={7}{2}

Hopes this helps also will you mind giving me brainliest?

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3 years ago

Which is a true statement about an isosceles right triangle?

AnnyKZ [126]

Let $l$ be the length of a leg. Using the pythagorean theorem, the hypotenuse is

$h = \sqrt{l^2+l^2}=\sqrt{2l^2}=l\sqrt{2}$

So, the hypotenuse is $\sqrt{2}$ times as long as either leg.

6 0

3 years ago

A recent kellogg survey shows that approximately 34% of americans eat breakfast. suppose alex takes a random sample of four amer

vlabodo [156]

This kind of experiments are ruled by Bernoulli's formula. If you have probability p of "success", and you want k successes in n trials, the probability is

$\binom{n}{k}p^k(1-p)^{n-k}$

It's easier to compute the first probability by difference: instead of computing the probability of the event "at least one of the surveyed eats breakfast", let's compute the probability of its contrary: none of them eats breakfast. So, we want 0 successes in 4 trials, with probability of success 0.34. The formula yields

$\binom{4}{0} 0.34^0 0.64^4 = 0.64^4 \approx 0.17 = 17\%$

Since the contrary has probability 17%, our event "at least one of the surveyed eats breakfast" has probability 83%.

As for the second question, the event "at least three of the surveyed eats breakfast" is the union of the events "exactly three of the surveyed eats breakfast" and "exactly four of the surveyed eats breakfast". So, we just need to sum their probabilities:

$\binom{4}{3} 0.34^3 0.64^1 +\binom{4}{4} 0.34^4 0.64^0 = 4\cdot 0.34^3 0.64 + 0.34^4 \approx 0.11 = 11\%$