3 years ago

Find the value of in the isosceles triangle shown below. 10 10 8

1 answer:

6 0

Hiiioo I will believe you us a² + b² = c² solve this ( pythagorean theorem ) but I could be wrong but I got 164 as my answer!

You might be interested in

Jerry painted 1/6 of his house on Saturday morning and 3/6 of his house on Monday morning . How much of his house does he have L

Leviafan [203]

Answer:

B-2/6

Step-by-step explanation:

three will subract the one since they all have the same dinominaters where by the answer is B

7 0

4 years ago

Larry’s family made a donation to the library. His mom gave half as much as larry. His dad gave 5 times as much as Larry’s siste

storchak [24]

Answer:

The family donated $52.50

Step-by-step explanation:

Larry's mom donated $7.50 ($15 ÷ $2=$7.50)

Larry's dad donated $25.00 ($5 x $5=$25.00)

Larry's sister donated $5.00 ($15 - $10=$5.00)

Larry donated $15.00

6 0

3 years ago

Deepa has 57. She has 4 times as much money as Gaurav. How much

Readme [11.4K]

Answer:

42.75 dollars more

Step-by-step explanation:

57/4= 14.25

Gaurav has 14.25 dollars

57-14.25=42.75

therefore Deepa has 42.75 more dollars than Gaurav

6 0

3 years ago

Dustin makes $2330 each month and pays $840 for rent. To the nearest tenth of a percent, what percent of Dustin's earning are sp

MariettaO [177]

$840 is roughly 36 percent of $2,330, when rounded to the nearest tenth Dustin spends 40% on rent.

3 0

3 years ago

How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen

VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

$4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4$

$48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128$

We can choose exactly three fives from five-card hands in $4C3*48C3$ ways.

$4C3*48C3=4*1128=4512$

Therefore, 4512 five card hands contain exactly three fives.

4 0

4 years ago