First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10
an = a1 * r^(n-1)
n = term to find = 5
a1 = first term = 120
r = common ratio = 3/10
now we sub and solve
a5 = 120 * 3/10^(5 - 1)
a5 = 120 * 3/10^4
a5 = 120 * .0081
a5 = 0.972 <=== fifth term
or we could have just done this......since we multiply by 3/10 to find the next number...
a3 = 10.8......10.8 * 3/10 = 3.24 <== 4th term
3.24 * 3/10 = 0.972 <== fifth term
Theo ran 3K in 9.6 minutes:
9.6 divided by 3 = 1.2 munutes
3 divided by 3 = 1k
1k = 1.2 minutes.
Estaban ran 5k in 13.5 minutes:
13.5 divided by 5 = 2.7 minutes
5 divided by 5 = 1k
1k = 2.7 munutes
Tetsuo ran 10k in 31.9 minutes:
31.9 divided by 10 = 3.19 munites
10 divided by 10 = 1k
1k = 3.19 minutes
Answer: Theo Ran the Fastest and all the writing above is the resoning.
F(-3)=(-3)2 - 1 / -3 + 4
f(-3)= -6 -1 / -3 + 4
f(-3)= -7/1
f(-3)=-7
