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lina2011 [118]
3 years ago
6

So what is 1.025 as a percent?

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

1.025%

Step-by-step explanation:

1.025 / 100 = 1.025%

Hope this helps

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Consider the following set of equations:
alina1380 [7]
B. x+4=3x+6 ..........
3 0
3 years ago
X=2y-1 <br> 3x+4y=11<br> Need help solving
tigry1 [53]

Answer: (-1/5, 2/5)


Step-by-step explanation:

See the photo for explanation and work.


6 0
3 years ago
If three times a number minus 2 equals 13, what is the number?
Nana76 [90]
Change the messy words into numerals
3     times          a number         minus            2           equals         13
3          ×                n                     -                 2               =               13

3n - 2 = 13
take 2 to the other side
3n - 2 + (2)  = 13 + (2)
3n = 15

Divide by 3 on either sides to isolate n
\frac{3n}{3} = \frac{15}{3}
3 and 3 cancels out

n = 5

check:
3 times 5 minus 2 equals 13
3     ×    5       -      2     =     13
15    -      2        =          13
13            =               13

The number is 5
3 0
3 years ago
Mai and Jada are both running on a treadmill. Mai travels 5 miles in 15 minutes. Jada travels 4 miles in 14 minutes. Who ran at
sasho [114]

Answer:

Mai

Step-by-step explanation:

To find the rate, you must determine who is going faster per minute. To do this, you must divide the total number of miles by the total number of minutes.

Mai: 5 miles / 15 minutes = 1/3 miles per minute

Jada: 4 miles / 14 minutes = 2/7 miles per minute

Then, use a common denominator to make calculations easier:

Mai: 1/3 * 7/7

Jada: 2/7 * 3/3

You should get:

Mai: 7/21 miles per minute

Jada: 6/21 miles per minute

By looking at this, you can see that Mai is traveling slightly faster, going more miles than Jada per minute.

3 0
3 years ago
Find the slope of the line that passes through (4,-5) and (-2,9)
stiks02 [169]

Answer:

C) -7/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(9-(-5))/(-2-4)=(9+5)/-6=14/-6

simplify -14/6 to -7/3

4 0
3 years ago
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