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2 years ago

What 10 to the 14th power

2 answers:

8 0

100,000,000,000,000
Anytime you are doing 10 to any power, just add that many zeros to 1.
i.e.
10 to the 5th power = 100,000 or 1 with five zeros
10 to the 10th power = 10,000,000,000 or 1 with 10 zeros

Aleksandr-060686 [28]2 years ago

6 0

10^14 = 100,000,000,000,000

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Harlamova29_29 [7]

Answer: I really dont know sorry

Step-by-step explanation:

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3 years ago

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Tony gets paid $5 per hour to babysit his cousin. This

Kaylis [27]

Answer:

Step-by-step explanation:

lets substitute 5 into every equation. (using 5 every time won't work every time ofc)

ok so 5(x+6)=55 would simplify into 5x+30=55 which in this case would be 5(5)+30=55 

and 25 plus 30 (obviously) = 55

so A is the right answer

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2 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

3 0

2 years ago

I need help finding the are of this

Allisa [31]

Answer:

78.5

Step-by-step explanation:

3.14*5*5=78.5

3 0

3 years ago

A lawn mower is pushed a distance of 100 ft. Along a horizontal path by a constant force of 60 lbs. Yhe handle of the lawn mower

olga2289 [7]

For this case we have the following equation:
w = || F || • || PQ || costheta
Where,
|| F ||: force vector module
|| PQ ||: distance module
costheta: cosine of the angle between the force vector and the distance vector.
Substituting values:
w = (60) * (100) * (cos (45))
w = 4242.640687 lb.ft
Answer:
The work done pushing the lawn mower is:
w = 4242.640687 lb.ft

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3 years ago