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swat32
3 years ago
11

What percent of 8 is 20

Mathematics
1 answer:
gavmur [86]3 years ago
3 0
You write it as a improper fraction first*
 20
-----
  8
and then u divide 8 into 20 
and we know that it goes in it 2.5 times
so simply from here
it is 2.5%
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Fill in what’s missing from the chart. Remember, graphing means to plot the values in your table.
Delicious77 [7]

Answer:

(for the second one)

y = 4x + 10

solution:

so first you have to find the slope, there is an equation for it. it is y2 - y1/ x2 - x1 or just y1 - y2/ x1 - x2 . so input the easiest points. id say f(0) and f(1)

so it will look like

2 - 6/0 - 1

-4/-1

4

so you can now write the equation as

y = 4x + b

now you have to find the y-intercept so input a point. i dont think you should input a point you used to find the slope because you could have made a mistake calculating so lets input f(2)

sooo

18 = 4(2) + b

18 = 8 + b

b = 10

so the function for the second one is y = 4x + 10

4 0
3 years ago
Read 2 more answers
What is the answer to 4+2(x-3)=-8
Afina-wow [57]

Answer: x= -3

Step By Step Explanation:

3 0
3 years ago
12x+3=6<br> to<br> 4x+1=2<br> Please explain how it went from first one to second one.
GuDViN [60]
Divide 12x+3=6 by 3. 12x/3=4x, 3/3=1, 6/3=2.
7 0
3 years ago
Point G is in love segment FH give an FH equals 4XGH equals XNFG Eagles 2X +10 determine the numerical link of FG
victus00 [196]

Answer:

FG= 30

Step-by-step explanation:

Point G is on line Segment FH

Given

FH= 4x

GH= x

FG= 2x+10

If the point G is on the line FH then the total of the two line segement FG and GH must be equal to FH

FH= FG+ GH

Putting the values in the above equation:

4x= 2x+10+x

4x= 3x+10  Solving for x

10= 4x-3x

10= x

FG= 2x +10

FG = 2(10) +10   Putting the value of x

FG= 20+10

FG= 30

Check :

FH= 4x= 4(10)= 40

GH= x= 10

FG = FH- GH= 40-10= 30

7 0
3 years ago
What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

3 0
3 years ago
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