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kotegsom [21]
3 years ago
6

Ow many three-letter "words" can be made from 8 letters "FGHIJKLM" if repetition of letters

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0

Answer:

336

Step-by-step explanation:

Lyrx [107]3 years ago
7 0
Nabsbskagsgjsjskaka skjava kajwbw akhaha kajw
You might be interested in
Hlp!
zzz [600]

Answer:

Option B

x ≥ (-5)

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • -3(x + 4) ≥ x + 8

So,

-3(x + 4) ≥ x + 8

-3x – 12 ≥ x + 8

Add both sides 12 we get,

-3x – 12 + 12 ≥ x + 8 + 12

-3x ≥ x + 20

Similarly, subtract x from both sides we get,

-3x – x ≥ x – x + 20

-4x ≥ 20

Then, divide both sides by (-4) we get,

-4x/(-4) ≥ 20/(-4)

x ≥ -5

Thus, The answer is x ≥ (-5).

7 0
2 years ago
The population of a town is decreasing at a rate of 3.2% per year. In 2015, there were 14,250 people. What is the first year tha
notsponge [240]
The answer is D
you would set up an equation like this
14,250 x .032
this will give you how much the population is decreasing per year. Which is 456 people per year.
You then take 2015 and find the difference between that number and 2025 and do it with all of the other years too.
For example 2025-2015 is 10 years
You then take 10 x 456 to tell you how much the of population you lost in those 10 years. You will then take that number which is 4,560 and do 14,250-4,560 to get 9,650.
4 0
2 years ago
I REALLY need help with these 3 questions plz!!!!
Tanzania [10]

Answer:

6. No. See explanation below.

7. 18 months

8. 16

Step-by-step explanation:

6. To rewrite a sum of two numbers using the distributive property, the two numbers must have a common factor greater than 1.

Let's find the GCF of 85 and 99:

85 = 5 * 17

99 = 3^2 + 11

5, 3, 11, and 17 are prime numbers. 85 and 99 have no prime factors in common. The GCF of 85 and 99 is 1, so the distributive property cannot be used on the sum 85 + 99.

Answer: No because the GCF of 85 and 99 is 1.

7.

We can solve this problem with the lest common multiple. We need to find a number of a month that is a multiple of both 6 and 9.

6 = 2 * 3

9 = 3^2

LCM = 2 * 3^2 = 2 * 9 = 18

Answer: 18 months

We can also answer this problem with a chart. We write the month number and whether they are home or on a trip. Then we look for the first month in which both are on a trip.

Month                Charlie          Dasha

1                          home             home

2                          home             home

3                          home             home

4                          home             home

5                          home             home

6                         trip                home

7                          home             home

8                          home             home

9                          home             trip

10                         home             home

11                         home             home

12                         trip               home

13                         home             home

14                         home             home

15                         home             home

16                         home             home

17                         home             home

18                         trip                 trip

Answer: 18 months

8.

First, we find the prime factorizations of 96 an 80.

96 = 2^5 * 3

80 = 2^4 *5

GCF = 2^4 = 16

Answer: 16

7 0
3 years ago
In a jar, there is a green, a blue, and a red marble. You draw (with replacement) a marble from the jar until you get the green
denpristay [2]

Answer:

The value is P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}

Step-by-step explanation:

From question we are told that

   The number of types of marbles present jar is n  =  3

Generally the probability of drawing a green marble is  

     P(g) =  \frac{1}{3}

Generally the probability of drawing a marble that is not green is  

     P(g') =  1 - \frac{1}{3} = \frac{2}{3}

From the question we are told that there will be continuous drawing of marbles from the jar (in such a way that after each marble is drawn it is being replaced) until a green marble drawn

  Let m be the number of times marbles has been drawn when a green marble was gotten

it then means that for m - 1 times the marbles where drawn a green marble was not obtain.

Generally the probability drawing m times is mathematically is mathematically represented as

    P( X = m ) = (P(g'))^{m-1 } * P(g)

=>  P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}

7 0
3 years ago
Hurry!!
zavuch27 [327]
For this case what you should see is the behavior of each function to find the correct answer.
 We have functions of the type:
 f (t) = a * (b) ^ t
 Thus,
 For I, we have:
 f (t) = 30 * (1.05) ^ t
 For V we have:
 f (t) = 30 * (0.95) ^ t
 For VI we have:
 f (t) = 30 * (0.85) ^ t
 Answer:
 option c.
8 0
3 years ago
Read 2 more answers
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