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2 years ago

True or false? The value zc is a value from the standard normal distribution such that P(−zc < z < zc) = c.

Mathematics

1 answer:

rewona [7]2 years ago

5 0

Answer:

False

Step-by-step explanation:

The standard normal distribution is represented by P(-zc < z < zc) = c

From this, you see that -zc is less than the variable of interest z and z is less than zc.

The equation simply means that the probability that -zc is less than z and z is less than zc, is c.

The value zc is NOT a value from the above distribution. All values in the distribution are of the variable z. For example, z might be equal to 1, z might be equal to 6, but the variable of interest in the distribution is z, not zc.

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Answer:

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

Step-by-step explanation:

We need to solve the equation for all real solutions in simplest form.

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First simplifying the equation:

$z^2 - 12z +9+3= -3+3\\z^2 - 12z +12= 0$

Now, we can solve the equation using quadratic formula:

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Putting values in formula and finding values of x

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So, we get value of z: z=10.9 or z=1.1

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