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Aliun [14]
3 years ago
9

True or false? The value zc is a value from the standard normal distribution such that P(−zc < z < zc) = c.

Mathematics
1 answer:
rewona [7]3 years ago
5 0

Answer:

False

Step-by-step explanation:

The standard normal distribution is represented by P(-zc < z < zc) = c

From this, you see that -zc is less than the variable of interest z and z is less than zc.

The equation simply means that the probability that -zc is less than z and z is less than zc, is c.

The value zc is NOT a value from the above distribution. All values in the distribution are of the variable z. For example, z might be equal to 1, z might be equal to 6, but the variable of interest in the distribution is z, not zc.

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a pet store buys bags of dog food for 30.00 dollars per bag and sells them for 54.00 dollars per bag. What is the percent markup
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Answer:

80%

Step-by-step explanation:

(54-30)/30 *100 = 80%

7 0
3 years ago
Samantha bought 10 identical shirts for $25. If she bought 25 of those same shirts, how much will she pay?
tatiyna

Answer:

72.50

Step-by-step explanation:

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2 years ago
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lidiya [134]

Answer:

  a)  No. t < 0 is not part of the useful domain of the function

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Step-by-step explanation:

a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.

__

b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.

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This has t-intercepts where the factors are zero, at t=-1/4 and t=2.

The ball will hit the ground after 2 seconds.

4 0
3 years ago
I'll mark you brainlist and give you 5 star I just need a lot of help
Softa [21]
ANSWER: M(-9,-4) to M’(-5,2)
If (x,y) is to (x+4,y+6)
Then (-9,-4) is to (-9+4,-4+6)
Hence (-9,-4) is to M’(-5,2)
Hopefully it’s correct
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lbvjy [14]
The answer is: B. 2:5
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