X intercept = -1, y = 0 (-1, 0)
<span>y intercept = 2, x = 0 (0, 2)
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slope between (-1, 0) and (0, 2):
slope = (2 -0)/(0 - -1) = 2/1 = 2, m = 2
Using point (-1, 0) x₁ = -1, y₁ = 0
y - y₁ = m(x - x₁)
y - 0 = 2*(x - -1)
y = 2(x + 1)
y = 2x + 2
Answer:
i think the second one
Step-by-step explanation:
i think it would be the smartest thing to pick
Answer:
66 ≤ f ≤100
Explanation
Mean= ( Σ x ) / n
Mean= sum of scores/ number of subject she took
Now, she already too 3 subject which sum is 85+83+86=254
Now we need to know range of score for her to have (grade) a mark between 80 and 89
Now let take the lower limit mean=80
The lowest score she can get is
Mean = ( Σx) / n
80=(85+83+86+f)/4
80×4= 254+f
Therefore, f= 320-254=66
Therefore the minimum score she can have to have a B is 66.
Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.
Mean = ( Σx) / n
89=( 83+85+86+f)/4
89×4= 254+f
f= 356-254
f=102.
Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.
There the range of score is 66 ≤ f ≤100 to have a B grade
66 ≤ f ≤100 answer
Since she cannot score 102 in the examination.
To solve this, you will have to set up your equation as fractions:
X is to 4 as 4 is to 4+3, or 7
X/4 = 4/7
You will then cross multiply
7x = 4•4
7x = 16
Divide.
X = 2.285714...
Round to the nearest hundredth.
2.29
