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katrin2010 [14]
2 years ago
11

Hi I know this seems like much but I really need help with all of this please

Mathematics
2 answers:
jeyben [28]2 years ago
6 0

Answer:

Step-by-step explanation:

1) 14

2) 3

3) 25-3=22

4) 64/4=8

5) 5*6=30

6) 4*12/6=8

7) 3+17=20

8) 84/6=14

9) 11+4=15

10) 24/6=4

Andru [333]2 years ago
6 0

Answer:

v²-3 where v equals 5 = 22

h^3÷ 8 where h equals 4 = 8

5(n-4) where n equals 10 = 30

4p ÷ 6 where p equals 12 = 8

6s + 17 where s equals 1/2 = 20

(3+g²) ÷ 6 where g equals 9 = 14

2f+1+6 where f equals 5 and g equals 4 = 15

(15+r) ÷q where r equals 9 and q equals 6 = 4

Step-by-step explanation:

Uhh it's kinda hard to explain but if you need a step-by-step explanation just comment that need one, I'd be happy to help :)

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1.59 meters is the correct answer i think.

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Let f(x) = 2x^2 - 4x + 1 <br><br> Find the values of f(1), f(0), f(2), f(-2), f(a)
Nataly [62]

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5 0
3 years ago
Somebody please help me
Olenka [21]
3p < 12
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and
-3p < 12
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-4< p < 4
It's C. third  one
5 0
3 years ago
Find each angle measure Make sure to give all 3
Grace [21]

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3 0
3 years ago
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How to solve and respond.
son4ous [18]

Step-by-step explanation:

the error:

it is stated that

\frac{5x}{x+7} +\frac{7}{x} = \frac{5x}{x+7} +\frac{7(7)}{x+7}

subtract (5x)/(x+7) from both sides

\frac{7}{x}  = \frac{7(7)}{x+7}

multiply both sides by x + 7

7(x+7) = 49x

7x + 49 = 49x

subtract 7x from both sides to isolate x and its coefficient

49 = 42x

thus, this is only true when 49 = 42x. in order for these two equations to be equal, they must <em>always </em>be true, so this is wrong

the solution:

we want to express 7/x as (something) / (x+7). to do this, we can multiply 7/x  by 1.

anything divided by itself = 1. thus, if we multiply both the numerator and the denominator by something that turns x into (x+7), we can do what we want to do.

(x+7)/x * x turns x into (x+7), so we multiply both the numerator and denominator by (x+7)/x to get

\frac{7}{x} = \frac{7(x+7)/x}{x+7}

substitute this for 7/x in our original problem

\frac{5x}{x+7} +\frac{7(x+7)/x}{x+7} =  \frac{5x}{x+7} +\frac{(7x+49)/x}{x+7} = \frac{5x}{x+7} +\frac{7+49/x}{x+7} = \frac{5x+7+49/x}{x+7}

3 0
2 years ago
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