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3 years ago

6

Help me pls I need this grade

2 answers:

Ivahew [28]3 years ago

5 0

yes lol bigger hah trigger lol susush

sladkih [1.3K]3 years ago

5 0

Yes if the circle is bigger than the quadrilateral.

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Assign two variables for each problem, and write the equations. Do not solve.

GalinKa [24]

Call the amount of pineapple "P', and the amount of gingerale "G".

We know that a mix of pineapple and gingerale makes 200 cups. So:
$P+G=200$

We also know that double the pineapple (i.e. 2P) and triple the gingerale (i.e. 3G) makes 420 cups. So:
$2P+3G=420$

We can now solve by substitution:
$2P+3(200-P)=420$
$2P+600-3P=420$
$-P=-180$
$P=180$

$180+G=200$
$G=20$

For 420 cups we need 2P=360 cups of pineapple and 3G=60 cups of gingerale]

3 0

3 years ago

Locate the points of discontinuity in the piecewise function shown below.

algol13

Answer:

Step-by-step explanation:

The given piecewise function i

From the given function it is clear that function is divided at x=-1 and x=2. It means we check the discontinuity at x=-1 and x=2.

For x=-1,

LHL:

Since LHL ≠ f(-1), therefore the given function is discontinuous at x=-1.

For x=2,

LHL:

Since LHL ≠ f(2), therefore the given function is discontinuous at x=2.

Therefore, the correct option is A.

8 0

3 years ago

PQ is bisected at point R by MN. Which of the following I true about point R.

Stella [2.4K]

Answer:

C. R is the midpoint of PQ.

Step-by-step explanation:

Given that segment PQ is bisected at point R by MN.

It means PQ is divided into two parts at point R by the segment MN.

That is, PR = RQ

Hence, R is the midpoint of PQ.

It is not given that the segment MN is bisected by PQ.

So, R need not be the midpoint of MN.

Please refer to the attached figure for better understanding.

7 0

4 years ago

Read 2 more answers

The floor of a drawing room consists of 2000 tiles. Each of the tiles is rectangular in

wlad13 [49]

Step-by-step explanation:

<h2><u>☼︎</u><u>Given :</u></h2>

The floor of a drawing room consist of 2000 tiles .Each tiles is rectangular in shape , of dimensions ,30 cm × 20 cm.

$\rule{200pt}{3pt}$

<h2><u>☼︎</u><u>To Find :</u></h2>

Area of the room.

$\rule{200pt}{3pt}$

<h2><u>☼︎</u><u>Solution :</u></h2>

<u>~ Formula </u><u>U</u><u>s</u><u>e</u><u>d</u><u>:</u>

$\large{\blue{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}} \: \: {\blue{\bigstar}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

<u>~ Calculating the</u><u> Area of Tiles </u>

${➙ \: {\sf{ Area = Length \times Breadth}}}$

${➙ \: {\sf{ Area = 30 \times 20 }}}$

${\sf{➙ \: Area \: of \: 1 Tiles = {\purple{\bf{ 600 \: cm² }}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

<u>~ Calculating Area of the </u><u>Drawing Room :</u>

${➙ \: {\sf{ Area \: of \: Room \: = No. \: of \: Tiles \times Area \: of \: 1 \: Tile }}}$

${➙ \: {\sf{ Area \: of \: Room \: = 2000 \times 600 }}}$

${\qquad{\sf{ Area \: of \: Room \: = {\color{darkblue}{\bf{ 1200000 \: cm² }}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

<u>~ Therefore :</u>

❝ Area of the Drawing room is 1200000 cm² or 12000 m² . ❞

$\begin{gathered} \\ {\blue{\underline{\red{\rule{300pt}{9pt}}}}}\end{gathered}$

8 0

3 years ago

Read 2 more answers

A blank is a fraction with a denominator of 1

Advocard [28]

A whole number is a fraction with a denominator of one

5 0

4 years ago