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Aloiza [94]
3 years ago
15

A gumball machine has 330 red gumballs. If the red gumballs are 75% of the total number of gumballs, how many gumballs are in th

e gumball machine?
Mathematics
1 answer:
patriot [66]3 years ago
3 0
75% = 330 gumballs

Find 1%:
1% = 330 ÷ 75 = 4.4 gumballs

Find 100%:
100% = 4.4 x 100 = 440 gumballs.

Answer: 440 gumballs.
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Feliz [49]
The answer is 50, 175
5 0
2 years ago
Henry drew the model below of his yard. He said the perimeter of the yard is 48 feet. He knows that one side is 9 feet wide. How
saw5 [17]

Answer:

15 feets

Step-by-step explanation:

Perimeter of a rectangle = 2(l + w)

l = Length ; w = width

Perimeter, p = 48

Length of all sides

p = 2(l + w)

48 = 2(l + 9)

48 = 2l + 18

48 - 18 = 2l

30 = 2l

l = 30/2

l = 15

Length of the sides = 15 feets

8 0
3 years ago
Write an inequality that represents the statement “x is at most –5 or at least 7.” A. x < –5 or x > 7 B. x > –5 or x &l
Afina-wow [57]
<span>C. x ≤ -5 or x ≥ 7 D.</span>
8 0
3 years ago
My brain small so could you plz anwser his 6/11+ 2/ 3
Lena [83]

Answer:

1 7/33

Step-by-step explanation:

6/11 + 2/3 --> We need a common denominator

--> 11 x 3 = 33

33 is our common denominator

6 x 3 = 18

2 x 11 = 22

18/33 + 22/33 = 40/33

Convert to a mixed number

=> 1 7/33

Thus, we have our answer.

4 0
3 years ago
In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?
Gnom [1K]

Answer:

There is only one distinct triangle possible, with m∠N ≈ 33°.   i hope this helps :)

Step-by-step explanation:

In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?

There are no triangles possible.

There is only one distinct triangle possible, with m∠N ≈ 33°.

There is only one distinct triangle possible, with m∠N ≈ 147°.

There are two distinct triangles possible, with m∠N ≈ 33° or m∠N ≈ 147°.

7 0
3 years ago
Read 2 more answers
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