What's 1000-7?<br><br>question by:Kaneki

Please help me solve this!!

lyudmila [28]

Answer:

$x=\sqrt{-2},or,x=\sqrt{2}i$

Step-by-step explanation:

$-3x^2+11=17\\-3^2+11-(11)=17-(11)\\-3x^2=6\\x^2=-2\\x=\sqrt{-2}$ I don't know what level math you're taking but in lower level math this would be undefined, can't be simplified. But some higher levels simplify it with imaginary or complex number representations. So take your pick, but it's still undefined
$x=\sqrt{2}i$

5 0

3 years ago

Why Do i SUCK AT MATH!!!!!!!!!!!!!!!!! :(

blagie [28]

Answer:

Math is not a very easy subject and not everyone can master it.All that is needed are focus,dedication and confidence.You should try practicing in your weak areas or seek help to get a better understanding.

Step-by-step explanation:

I really hope this helps :)

8 0

3 years ago

Help me fast, please!!!!!!!!!!!!

Oksi-84 [34.3K]

I believe these are the answers:

1. True.

2. False.

3. False.

4. True.

Let me know if those are right. :)

7 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

zheka24 [161]

<h2>Hello!</h2>

The answer is:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$