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Ierofanga [76]
3 years ago
15

HELP ME PLS

Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Split the shape into 2 cuboids

7*2*5 = small cuboid

10*4*5 = large cuboid

add both of these figures up to find the total volume.

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Factor p 2 + 18p + 32.
zhenek [66]

The correct factorization is (p + 16)(p + 2).

You can find this by looking for factors of the final number that add up to the middle number. Factors of the final number are listed below:

1 * 32

-1 * -32

2 * 16

-2 * -16

4 * 8

-4 * -8

Now you select the one that adds to 18, which would be the highlighted 2 and 16. Now we use these in parenthesis with a p + in the front of it.

(p + 2)(p + 16)

This will be the correct factored form.

8 0
4 years ago
Read 2 more answers
Find the missing coordinate if the ordered pair is to be a solution to the equation 3x + y = 9: (?,-9)
maksim [4K]
X equals 6

hope this helps just plug in the y value int the equation and solve


6 0
3 years ago
what are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?
julsineya [31]

Answer:

\frac{\pi }{2} and \frac{3\pi }{2}

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

f(x) = 4cos(2x-\pi )\\f'(x)=-4sin(2x-\pi )(2)\\f'(x)=-8sin(2x-\pi )\\

Now we need to find when f'(x)=0 to find the critical values.

0=-8sin(2x-\pi )\\0=sin(2x-\pi )\\sin^{-1}0=2x-\pi \\0=2x-\pi \\\pi =2x\\\frac{\pi }{2} =x

The critical values will be

\frac{\pi }{2} n for any integer n

between 0 and 2 pi, the critical values will be

0, \frac{\pi }{2} ,\pi ,\frac{3\pi }{2},2\pi

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

f'(x)=-8sin(2x-\pi )\\f''(x) = -8cos(2x-\pi )(2)\\f''(x)=-16cos(2x-\pi)

We need to see if the second derivative is positive or negative to determine if it is a max or min.

f''(0) = 16\\f''(\frac{\pi}{2})=-16\\f''(\pi )=16\\f''(\frac{2\pi}{3}) = -16\\

Since the second derivative is negative at

\frac{\pi }{2} and \frac{3\pi }{2}

we know both of those are the x-values of maximums.

5 0
4 years ago
A line passes through the points (8,9) and (-2,4) .
MA_775_DIABLO [31]
A) Y1-Y2/X1-X2
9-4/8-(-2) = 5/10= 1/2

b) 1/2x+b=y <-- plug in a point
1/2(-2)+b=4 <--plugged in (-2,4)
-1+b=4 <-- simplify/solve
b=5

c) 1/2x+5=y
3 0
4 years ago
What is the answer: -4 - (-9)
expeople1 [14]
-4 -(-9)= -4 +9 = 9-4 =\boxed {5}
7 0
3 years ago
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