Question

X2+10x+24=(x+a)(x+a) B is An Interger Find Algebracally All Possible Values of. B

Answer 1

$(x+a)(x+a)=x^2+2ax+a^2\\\\ 2a=10 \wedge a^2=24\\ a=5 \wedge (a=\sqrt{24} \vee a=-\sqrt{24})\\ a=5 \wedge (a=2\sqrt{6} \vee a=-2\sqrt{6})$

The above is contradiction, so there are no such values of 'a'.