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3 years ago

14

You earn $0.85 for every cup of hot chocolate you sell. Write and solve an equation to determine how many cups you need to sell

to earn $55.25.

1 answer:

antoniya [11.8K]3 years ago

6 0

Answer:

47 rounding to nearest 100th

Step-by-step explanation:

Divide 55.25 into 0.85 and get 46.96 then round to get 47 cups.

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Expression when m=8 and n=7 n+6m

Andrews [41]

All you have to do is plug m and n into the equation:

n+6m

Since n=7, you'll get:

7+6m

And since m=8, you'll get:

7+6(8)

And by doing the order of operations (PEMDAS), you'll start off multiplying 6 and 8, which is 48, then add 7, which is 55.

Your answer should be 55!

7 0

3 years ago

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Can someone plz help me.

Arlecino [84]

Is there more than one answer to the problem. if so can I see them.

8 0

3 years ago

Just need the answer guys please

Mkey [24]

The first problem’s answer is true. (P.S. If you don’t understand this type of problems then plug in variables for them. It helps check your answer and solve them too.)

The second problem’s answer is false.

First of all, I plugged in for the variable a to be 6 for the first problem. Second, I plugged in numbers for the variables and x was 5 and x was 2 for the second problem. You can check the steps in the image I took. (P.S. You can use the MathPapa calculator online to solve these problems and plug in the variables.)

(I couldn’t upload the second problem’s step by step sorry, but if you need it then just use the MathPapa calculator by plugging in numbers for the variables.)

5 0

4 years ago

(X^2+x-6)(2x^2+4x) factor completely

MissTica

Answer:

$2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring $x^2+x-6$ .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For $ax^2+bx+c$ we need to find u, v > $u\cdot \:v=a\cdot \:c$ and $u+v=b$ which we will group into $\left(ax^2+ux\right)+\left(vx+c\right)$ .

The values we have are... $a=1,\:b=1,\:c=-6$ and $u\cdot v=-6,\:u+v=1$ .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

$\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow \mathrm{True}$

$\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow \mathrm{False}$

Therefore $u=3,\:v=-2$ .

Now we want to $\mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right)$ . Which is $\left(x^2-2x\right)+\left(3x-6\right)$ .

Now we must factor x from $x^2-2x$ .

Lets apply the exponent rule of $a^{b+c}=a^ba^c$ which means $x^2=xx$ .

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of $3x-6$ .

Rewrite 6 as 3 * 2. $3x-3\cdot \:2$ .

Now factor out the common term of 3 > $3\left(x-2\right)$ .

$x\left(x-2\right)+3\left(x-2\right)$ > Factor out the common term of x - 2 > $\left(x-2\right)\left(x+3\right)$ .

Now lets factor $2x^2+4x$ .

Apply the previous exponent rule of $a^{b+c}=a^ba^c$ > $x^2=xx$ > $2xx+4x$ .

Now rewrite 4 as 2 * 2 > $2xx+2\cdot \:2x$ .

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get $2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$ .

Hope this helps!

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3 years ago

How can I factor this equation <br> X squared -9=

NARA [144]

Answer:

(x+3)(x-3)

Step-by-step explanation:

x^2 - 9

(x+3)(x-3)

This is a difference of two squares problem. Hope this helped :)

4 0

3 years ago

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