The given statement is a false statement because -12 is not equal to -15 and also -15 is less than -12 which are correct answers would be Options (A) and (D).
<h3>What is inequality?</h3>
Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.
The given statement as:
⇒ -12 ≤ -15
Since -12 and -15 are not equal and -15 is smaller than -12, the preceding statement is incorrect.
So the following statements are correct:
It is a false statement because -12 is not equal to -15.
It is a false statement because -15 is less than -12.
Hence, the given statement is a false statement because -12 is not equal to -15 and also -15 is less than -12 which are correct answers would be Options (A) and (D).
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Answer:
<h2> T<u>he Susans Bees lost by </u><u>
3</u><u> points.</u></h2>
Step-by-step explanation:
Rosie's Riveters has 13 points in all.
The Susans Bees have 10 points in all.
13 - 10 = 3.
Set up fractions and solve them
Answer:
The second answer - 40, 10, 20, 50
Step-by-step explanation:
Range is the difference between the largest and smallest number in a data set. The biggest and smallest numbers in the data set are 50 and 10, respectively. 50 - 10 = 40.
The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
<h3>How to determine the functions?</h3>
A quadratic function is represented as:
y = a(x - h)^2 + k
<u>Question #6</u>
The vertex of the graph is
(h, k) = (-1, 2)
So, we have:
y = a(x + 1)^2 + 2
The graph pass through the f(0) = -2
So, we have:
-2 = a(0 + 1)^2 + 2
Evaluate the like terms
a = -4
Substitute a = -4 in y = a(x + 1)^2 + 2
y = -4(x + 1)^2 + 2
<u>Question #7</u>
The vertex of the graph is
(h, k) = (2, 1)
So, we have:
y = a(x - 2)^2 + 1
The graph pass through (1, 3)
So, we have:
3 = a(1 - 2)^2 + 1
Evaluate the like terms
a = 2
Substitute a = 2 in y = a(x - 2)^2 + 1
y = 2(x - 2)^2 + 1
<u>Question #8</u>
The vertex of the graph is
(h, k) = (1, -2)
So, we have:
y = a(x - 1)^2 - 2
The graph pass through (0, -3)
So, we have:
-3 = a(0 - 1)^2 - 2
Evaluate the like terms
a = -1
Substitute a = -1 in y = a(x - 1)^2 - 2
y = -(x - 1)^2 - 2
Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
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