The question is incomplete. Here is the complete qeustion.
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15
(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.
(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?
Answer: (a) 0.089 ≤ μ ≤ 0.171
(b) No
Step-by-step explanation:
(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample
X = ![\frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B0.1%2B0.13%2B0.16%2B0.15%2B0.14%2B0.08%2B0.15%7D%7B7%7D)
X = 0.13
s = ![\sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B%280.1-0.13%29%5E%7B2%7D%20%2B%20%280.13%20-%200.13%29%5E%7B2%7D%20%2B%20...%20%2B%20%280.15%20-%200.13%29%5E%7B2%7D%7D%7B7-1%7D%20%7D)
s = 0.029
The degrees of freedom is
N - 1 = 7 - 1 = 6
And since the confidence is of 99%:
α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005
The t-test statistics for
is 3.707
(Value found in the t-distribution table)
Now, calculate Error:
E =
. ![\frac{s}{\sqrt{N} }](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B%5Csqrt%7BN%7D%20%7D)
E = 3.707. ![\frac{0.029}{\sqrt{7} }](https://tex.z-dn.net/?f=%5Cfrac%7B0.029%7D%7B%5Csqrt%7B7%7D%20%7D)
E = 0.041
The interval will be:
0.13 - 0.041 ≤ μ ≤ 0.13+0.041
0.089 ≤ μ ≤ 0.171
(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.