By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
To learn more on quadratic equations: brainly.com/question/17177510
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Answer:
the distance is 3/4
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)
2x-y=0 Y=x-1 2x-x-1=0 x-1=0
If y is directly proportional to x then y:x.
When y = 30, x = 6 then 30/6 = 5:1. Therefor for every 1x there is 5y vice versa. When x = 12, then y = 5 * 12 = 60.
Therefore y = 60 hence 60:12
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