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lozanna [386]
3 years ago
13

Milan is riding on a bike course that is 40 miles long so far he has ridden 22 miles of the course what percentage of the course

has Milan ridden so far
Mathematics
2 answers:
Svetllana [295]3 years ago
7 0

Answer:

55%

Step-by-step explanation:

nadezda [96]3 years ago
6 0

Answer:

its yo mama

Step-by-step explanation:

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Someone please help me in this please.
yan [13]

Answer:

for the number 13

Step-by-step explanation:

x =   \sqrt{9 { }^ {2} + 6 { }^{2}  }

by Pythagoras theorem

x= √81+36

x= √117

punch square root of 117 with a calculator, I don't have one now

7 0
3 years ago
Due in 5 mins please help me!
Alchen [17]

Answer:

no

Step-by-step explanation:

7 0
3 years ago
What is the image of the point (-1,-3) after a rotation of 90 ∘ counterclockwise about the origin?
AVprozaik [17]

Answer:

(-3,1)

Step-by-step explanation:

8 0
3 years ago
Janice bought 40 shares of stock at $31.82 per share. She received dividends of $1.11 per share for 1 year. What was her purchas
-BARSIC- [3]

Her purchase price was 40×($31.82-$1.11)=$4×307.1=$1228.4

4 0
4 years ago
Read 2 more answers
Assume you are given a boolean variable named isRectangular and a 2-dimensional array that has has been created and assigned to
Savatey [412]

Answer:

nElements = 0;

for (int i = 0; i < a2d.length; i++)

nElements += a2d[i].length;

isRectangular = true;

for (int i = 1; i < a2d.length && isRectangular; i++)

if (a2d[i].length != a2d[0].length)

isRectangular = false;

Step-by-step explanation:

2 dimensional array is created and  initialize element with 0. and the taking loop for 2 dimensional array .such as

n Elements = 0;

for (int i = 0; i < a2d.length; i++)

n Elements += a2d[i].length;

A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.

If rectangular is false then  apply if statement  and see if a2d[i] is not equal to a2d[0]

if (a2d[i].length != a2d[0].length)

isRectangular = false;

4 0
4 years ago
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